Hydraulics and Fluid Mechanics in ME When an ideal fluid flows past a sphere lowest pressure intensity occurs at front stagnation point lowest pressure intensity occurs at rear stagnation point total drag is zero highest intensity of pressure occurs around the circumference at right angles to flow lowest pressure intensity occurs at front stagnation point lowest pressure intensity occurs at rear stagnation point total drag is zero highest intensity of pressure occurs around the circumference at right angles to flow ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The flow rate in gear pump Unpredictable Increases with increase in pressure More or less remains constant with increase in pressure Decreases with increase in pressure Unpredictable Increases with increase in pressure More or less remains constant with increase in pressure Decreases with increase in pressure ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The maximum thickness of boundary layer in a pipe of radius r is 2r r/2 r 2r r/2 r ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME A hemispherical tank of radius (R) has an orifice of cross-sectional area (a) at its bottom and is full of liquid. The time required to empty the tank completely is 14π R7/2/15Cd × a √(2g) 14π R5/2/15Cd × a √(2g) 14π R3/2/15Cd × a √(2g) 14π R1/2/15Cd × a √(2g) 14π R7/2/15Cd × a √(2g) 14π R5/2/15Cd × a √(2g) 14π R3/2/15Cd × a √(2g) 14π R1/2/15Cd × a √(2g) ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME Head developed by a centrifugal pump depends on Fluid density Impeller diameter Speed Both (A) and (B) above Fluid density Impeller diameter Speed Both (A) and (B) above ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The discharge over a rectangular weir, considering the velocity of approach, is (whereH1 = H + Ha = Total height of water above the weir, H = Height of water over the crest of the weir, and Ha = Height of water due to velocity of approach) (2/3) Cd × L. √2g [H13/2 - Ha3/2] (2/3) Cd × L. √2g [H15/2 - Ha5/2] (2/3) Cd × L.√2g [H12 - Ha2] (2/3) Cd × L.√2g [H1 - Ha] (2/3) Cd × L. √2g [H13/2 - Ha3/2] (2/3) Cd × L. √2g [H15/2 - Ha5/2] (2/3) Cd × L.√2g [H12 - Ha2] (2/3) Cd × L.√2g [H1 - Ha] ANSWER DOWNLOAD EXAMIANS APP
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