Hydraulics and Fluid Mechanics in ME When a piping system is made up primarily of friction head and very little of vertical lift, then pump characteristics should be Nearly horizontal Horizontal First rise and then fall Steep Nearly horizontal Horizontal First rise and then fall Steep ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The meatcentric height is the distance between the Centre of gravity of the floating body and the metacentre Metacentre and centre of buoyancy Original centre of buoyancy and new centre of buoyancy Centre of gravity of the floating body and the centre of buoyancy Centre of gravity of the floating body and the metacentre Metacentre and centre of buoyancy Original centre of buoyancy and new centre of buoyancy Centre of gravity of the floating body and the centre of buoyancy ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME Choose the wrong statement. Alcohol is used in manometer, because Its vapour pressure is low It provides suitable meniscus for the inclined tube It provides longer length for a given pressure difference Its density is less Its vapour pressure is low It provides suitable meniscus for the inclined tube It provides longer length for a given pressure difference Its density is less ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME Which of the following hydraulic unit is used for transmitting increased or decreased torque to the driven shaft? Hydraulic torque converter Hydraulic accumulator Hydraulic ram Hydraulic intensifier Hydraulic torque converter Hydraulic accumulator Hydraulic ram Hydraulic intensifier ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME Which type of the pump is different from others in the same group? Plunger pump Gear pump Cam and piston pump Screw pump Plunger pump Gear pump Cam and piston pump Screw pump ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME A tank of uniform cross-sectional area (A) containing liquid upto height (H1) has an orifice of cross-sectional area (a) at its bottom. The time required to empty the tank completely will be (2AH₁²)/(Cd × a√2g) (2AH₁)/(Cd × a√2g) (2AH₁3/2)/(Cd × a√2g) (2A√H₁)/(Cd × a√2g) (2AH₁²)/(Cd × a√2g) (2AH₁)/(Cd × a√2g) (2AH₁3/2)/(Cd × a√2g) (2A√H₁)/(Cd × a√2g) ANSWER DOWNLOAD EXAMIANS APP
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