Machine Design When a close coiled helical spring is compressed, its wire is subjected to Compression Tension All of these Shear Compression Tension All of these Shear ANSWER DOWNLOAD EXAMIANS APP
Machine Design If T₁ and T₂ are the tensions on the tight and slack sides of the belt respectively, and Tc is the centrifugal tension, then initial tension in the belt is equal to (T₁ - T₂ + Tc)/2 (T₁ + T₂ + Tc)/2 T₁ - T₂ + Tc T₁ + T₂ + Tc (T₁ - T₂ + Tc)/2 (T₁ + T₂ + Tc)/2 T₁ - T₂ + Tc T₁ + T₂ + Tc ANSWER DOWNLOAD EXAMIANS APP
Machine Design According to maximum normal stress theory, the maximum normal stress in the shaft is (1/2) × [σ + √(σ² × 4τ²)] √(σ² × 4τ²) (1/2) × √(σ² × 4τ²) σ + √(σ² × 4τ²) (1/2) × [σ + √(σ² × 4τ²)] √(σ² × 4τ²) (1/2) × √(σ² × 4τ²) σ + √(σ² × 4τ²) ANSWER DOWNLOAD EXAMIANS APP
Machine Design If T is the actual number of teeth on a helical gear and φ is the helix angle for the teeth, then formative number of teeth is written as T sec²φ T/sec³φ T sec³φ T cosecφ T sec²φ T/sec³φ T sec³φ T cosecφ ANSWER DOWNLOAD EXAMIANS APP
Machine Design In a band and block brake, the ratio of tensions on the tight and slack sides of band is given by (where μ = Coefficient of friction between the blocks and the drum, θ = Semi-angle of each block subtending at the centre of drum, and n = Number of blocks) T₁/T₂ = [(1 - μ tanθ)/ (1 + μ tanθ)]n T₁/T₂ = [(1 + μ tanθ)/ (1 - μ tanθ)]n T₁/T₂ = μθ × n T₁/T₂ = (μθ)n T₁/T₂ = [(1 - μ tanθ)/ (1 + μ tanθ)]n T₁/T₂ = [(1 + μ tanθ)/ (1 - μ tanθ)]n T₁/T₂ = μθ × n T₁/T₂ = (μθ)n ANSWER DOWNLOAD EXAMIANS APP
Machine Design The shock absorbing capacity of a bolt can be increased by Making shank diameter equal to core diameter of thread Grinding the shank Tightening it properly Increasing shank diameter Making shank diameter equal to core diameter of thread Grinding the shank Tightening it properly Increasing shank diameter ANSWER DOWNLOAD EXAMIANS APP
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