Let X and Y are given fractions.Given that, fraction X is thrice the fraction Y;i.e., X = 3Y ...(1)And their product = X x Y = 25/12Sub. eqn (1) in above,(3Y)x(Y) = 25/123(Y²) = 25/12(Y²) = 25/36Y = 5/6Hence the required fraction is 5/6.
Length of each piece = 3 1/4 = 13/4 m Maximum pieces that can be cut = 30/(13/4) = 9 ∴ Rope left = 30 - 13/4 x 9 = 120 - 117/4 = 3/4 m∴ Required fraction = 3/4/30 = 1/4
We have to find X such that 4/5 < X < 6/7Converting each fraction into decimal form, we get:4/5 = 0.86/7 = 0.85We have to find the fraction which is greater than 0.8 and less than 0.85.Now,2/3 = 0.663/4 = 0.755/6 = 0.8310/11 = 0.91Clearly, 0.83 lies between 0.8 and 0.85.Required fraction is 5/6
EXAMIANS