Fractions and Decimals When .36 is written in simplest fractional form, the sum of the numerator and the denominator is : 29 34 23 37 29 34 23 37 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 0.36 = 36 / 100 = 9 / 25. Sum of Numerator and Denominator = 9 + 25 = 34.
Fractions and Decimals √441.441 + √256.256 = ? 35 37 41 39 35 37 41 39 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP ? = √441.441 + √256.256= √441 + √256= (21 + 16) = 37
Fractions and Decimals 8.32 x 0.999 = ? 8.31168 8311.68 83.1168 831.168 8.31168 8311.68 83.1168 831.168 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given expression = 8.32 x 0.999= 8.32 x (1-0.001) = 8.32 - 8.32 x 0.001=8.32 - .00832 = 8.31168
Fractions and Decimals The value of [0.1 x 0.1 x 0.1 + 0.02 x 0.02 x 0.02] / [0.2 x 0.2 x 0.2 + 0.04 x 0.04 x 0.04] is: 125 1.25 0.125 12.5 125 1.25 0.125 12.5 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given expression=[(0.1)³ + (0.02)³] / 2³ [(0.1)³ + (0.02)³]=1/8= 0.125
Fractions and Decimals The number 0.127 is how much greater than 1/8 ? 1/1000 1/300 1/800 1/500 1/1000 1/300 1/800 1/500 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 0.127 expressed as a fraction = 127/10001/8 can also be expressed as (1 x 125) / (8 x 125) = 125/1000The difference is 2/1000, which is 1/500
Fractions and Decimals The price of commodity X increases by 40 paise every year, while the price of commodity Y increases by 15 paise every year. If in 2001, the price of commodity X was Rs. 4.20 and that of Y was Rs. 6.3 2014 2012 2011 2013 2014 2012 2011 2013 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Suppose commodity X wil cost 40 paise more than Y after Z years.Then, (4.20 + 0.40Z) - (6.30 + 0.15Z) = 0.40 0.25Z = 0.40 + 2.10 Z= X will cost 40 paise more than Y 10 years after 2001 . i.e in 2011
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