Fractions and Decimals What will come in place of question mark in the following equation ? 54.(?)3 + 543 + 5.43 = 603.26 7 3 5 8 7 3 5 8 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let x + 543 + 5.43 = 603.26.Then, x = 603.26 - (543 + 5.43) = 603.26 - 548.43 =54.83Missing digit = 8.
Fractions and Decimals If the numerator of a fraction is increased by 2 and denominator is increased by 3, the faction becomes 7/9 and if numerator as well as denominator are decreased by 1, the fraction becomes 4/5. What i 5/6 5/8 5/4 5/10 5/6 5/8 5/4 5/10 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the numerator and denominator be p and q respectively.Then, (p + 2) / (q + 3) = 7/9⇒ 9(p + 2) = 7(q +3)⇒ 9p - 7q = 3 ....(i)Again, (p - 1) / (q - 1) = 4/5⇒ 5p - 4q = 1 ....(ii)Solving (i) and (ii) we get,p = 5, q = 6Required fraction = 5/6
Fractions and Decimals [{(0.1)² - (0.01)²} / {0.0001 + 1 }] is equal to ? 25 50 75 100 25 50 75 100 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given expression = (0.01 - 0.0001) / (0.00001 + 1)= (.0099 / .0001) + 1 = 99 + 1= 100
Fractions and Decimals The expression (11.98 * 11.98 + 11.98 * (x) + 0.02 * 0.02) will be a perfect square for x equal to : None of these 4 0.04 0.4 None of these 4 0.04 0.4 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given = (11.98)^2 + (0.02)^2 + 11.98 * x. For the given expression to be a perfect square, we must have11.98 * x = 2 * 11.98 * 0.02=> x = 0.04
Fractions and Decimals The price of commodity X increases by 40 paise every year, while the price of commodity Y increases by 15 paise every year. If in 2001, the price of commodity X was Rs. 4.20 and that of Y was Rs. 6.3 2014 2012 2013 2011 2014 2012 2013 2011 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Suppose commodity X wil cost 40 paise more than Y after Z years.Then, (4.20 + 0.40Z) - (6.30 + 0.15Z) = 0.40 0.25Z = 0.40 + 2.10 Z= X will cost 40 paise more than Y 10 years after 2001 . i.e in 2011
Fractions and Decimals 3 x 0.3 x 0.03 x 0.003 x 30=? 2.430 0.2430 0.002430 0.02430 2.430 0.2430 0.002430 0.02430 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 3 x 3 x 3 x 3 x 30 = 2430 ∴ 3 x 0.3 x 0.03 x 0.003 x 30 = 0.002430 (Six places of decimal
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