Fractions and Decimals What will come in place of question mark in the following equation ? 54.(?)3 + 543 + 5.43 = 603.26 5 8 7 3 5 8 7 3 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let x + 543 + 5.43 = 603.26.Then, x = 603.26 - (543 + 5.43) = 603.26 - 548.43 =54.83Missing digit = 8.
Fractions and Decimals (369.99)² = ? None of these 1369 1369 x 10 1369 x 10² None of these 1369 1369 x 10 1369 x 10² ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 1369 x 10²
Fractions and Decimals ( .803 x .647 + .803 x .353 ) = ? .803 8.03 803 80.3 .803 8.03 803 80.3 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given Expression = ( .803 x .647 + .803 x .353 )= 803 x (.647 + .353)= .803 x 1 = .803
Fractions and Decimals ( 0.5 x 0.5 x 0.5 x 0.6 x 0.6 x 0.6 ) / ( 0.5 x 0.5 - 0.3 + 0.6 x 0.6 ) = ? 11 11.1 111.1 1.1 11 11.1 111.1 1.1 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given expression = [(0.5)³ + (0.6)³ ] / [(0.5)² - 0.5 x 0.6 + (0.6)²]= (a³+b³) / ( a²-ab+b²)= a + b= 0.5 + 0.6= 1.1
Fractions and Decimals The price of commodity X increases by 40 paise every year, while the price of commodity Y increases by 15 paise every year. If in 2001, the price of commodity X was Rs. 4.20 and that of Y was Rs. 6.3 2012 2014 2011 2013 2012 2014 2011 2013 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Suppose commodity X wil cost 40 paise more than Y after Z years.Then, (4.20 + 0.40Z) - (6.30 + 0.15Z) = 0.40 0.25Z = 0.40 + 2.10 Z= X will cost 40 paise more than Y 10 years after 2001 . i.e in 2011
Fractions and Decimals (6.5 x 4.7 + 6.5 x 5.3 ) / (1.3 x 7.9 - 1.3 x 6.9) = ? 60 65 50 55 60 65 50 55 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given Expression = (6.5 x 4.7 + 6.5 x 5.3 ) / (1.3 x 7.9 - 1.3 x 6.9) = [6.5 x (4.7 + 5.3 )] / [13 x (7.9 - 6.9)]= (6.5 x 10) / (1.3 x 1) = 50
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