Fractions and Decimals (0.2 * 0.2 + 0.01) ( 0.1 * 0.1 + 0.02)^(-1) is equal to : 7/3 4/3 5/3 6/3 7/3 4/3 5/3 6/3 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given = (0.2 * 0.2 + 0.01) / ( 0.1 * 0.1 + 0.02)= (0.04 + 0.01) / (0.01 + 0.02) = 0.05 / 0.03= 5/3...
Fractions and Decimals 6 x 0.6 x 0.06 x 0.006 x 60 = ? 7.776 0.07776 0.7776 77.76 7.776 0.07776 0.7776 77.76 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP ? = 6 x 6/10 x 6/100 x 6/1000 x 60 = 77760/1000000 = 7776/100000 = 0.07776
Fractions and Decimals (10.3 * 10.3 * 10.3 + 1)/(10.3 * 10.3 - 10.3 + 1) is : 111.3 1.3 None of these 11.3 111.3 1.3 None of these 11.3 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP a^3 + b^3 = (a+ b) * (a^2 + b^2 - ab)..( (10.3)^3 + (1)^3 ) / ((10.3)^2 + (1)^2 - (1 * 10.3))=> a + b = 10.3 + 1 = 11.3
Fractions and Decimals If the numerator of a fraction is increased by 2 and the denominator is increased by 1, the fraction because 5/8 and if the numerator of the same fraction is increased by 3 and the denominator is incr 3/7 2/7 4/7 1/7 3/7 2/7 4/7 1/7 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the original fraction be p/q Then, (p + 2) / (q + 1) = 5/8⇒ 8p - 5q = 11 .....(i)Again (p + 3) / (q + 1) = 3/4⇒ 4p - 3q = 9 ...(ii)Solving equations , (i) and (ii), we get ,p = 3 and q = 7∴ Fraction = 3/7
Fractions and Decimals If two-third of two-seventh of a number is 60, then two-fifteenth of that number is 56 34 71 42 56 34 71 42 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the number be X.Then 2/3 x 2/7 x X =60X = 60 x 7 x 3 / 4 = 315Then, 2/15 of 315 = 2/15 x 315 = 42.Hence the required number is 42
Fractions and Decimals A vessel, full of water, weighs 16.5 kg. When the vessel is (1/4)th full, it weight 5.25 kg. Then, weight of the empty vessel (in kg) is ? 1.5 kg 100.5 kg 10.5 kg 1000.5 kg 1.5 kg 100.5 kg 10.5 kg 1000.5 kg ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the weight of vesel = x kg Then, 1/4 of volume of water = (5.25 - x)kg Full volume of water = (16.5 - x)∴ 4(5.25 - x) = (16.5 - x)⇒ 21 - 4x = 16.5 - x ⇒ 21 - 16.5 = 3x ∴ x = 4.5/3 = 1.5 kg