Hydraulics and Fluid Mechanics in ME Water is _________ liquid. Both A and B An incompressible None of these A compressible Both A and B An incompressible None of these A compressible ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME A compound pipe of diameter d1, d2 and d3 having lengths l1, l2 and l3 is to be replaced by an equivalent pipe of uniform diameter d and of the same length (l) as that of the compound pipe. The size of the equivalent pipe is given by l/d⁵ = (l₁/d₁⁵) + (l₂/d₂⁵) + (l₃/d₃⁵) l/d⁴ = (l₁/d₁⁴) + (l₂/d₂⁴) + (l₃/d₃⁴) l/d³ = (l₁/d₁³) + (l₂/d₂³) + (l₃/d₃³) l/d² = (l₁/d₁²) + (l₂/d₂²) + (l₃/d₃²) l/d⁵ = (l₁/d₁⁵) + (l₂/d₂⁵) + (l₃/d₃⁵) l/d⁴ = (l₁/d₁⁴) + (l₂/d₂⁴) + (l₃/d₃⁴) l/d³ = (l₁/d₁³) + (l₂/d₂³) + (l₃/d₃³) l/d² = (l₁/d₁²) + (l₂/d₂²) + (l₃/d₃²) ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME A vessel of 4 m3 contains oil which weighs 30 kN. The specific weight of the oil is 7.5 kN/m3 4.5 kN/m3 10 kN/m3 6 kN/m3 7.5 kN/m3 4.5 kN/m3 10 kN/m3 6 kN/m3 ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The water in a jet propelled boat is drawn through the openings facing the direction of motion of the boat. The efficiency of propulsion is given by 2V/(vr - v) V/(vr - v) 2V/(vr + v) V/(vr + v) 2V/(vr - v) V/(vr - v) 2V/(vr + v) V/(vr + v) ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME According to Francis formula, the discharge over a rectangular weir is (where n = Number of end contractions) (2/3) × Cd (L - 0.1nH) × √(2g) × H3/2 (2/3) × Cd (L - nH) × √(2g) × H5/2 (2/3) × Cd (L - nH) × √(2g) × H² (2/3) × Cd (L - nH) × √(2gh) (2/3) × Cd (L - 0.1nH) × √(2g) × H3/2 (2/3) × Cd (L - nH) × √(2g) × H5/2 (2/3) × Cd (L - nH) × √(2g) × H² (2/3) × Cd (L - nH) × √(2gh) ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The discharge over a rectangular weir, considering the velocity of approach, is (whereH1 = H + Ha = Total height of water above the weir, H = Height of water over the crest of the weir, and Ha = Height of water due to velocity of approach) (2/3) Cd × L.√2g [H12 - Ha2] (2/3) Cd × L. √2g [H15/2 - Ha5/2] (2/3) Cd × L.√2g [H1 - Ha] (2/3) Cd × L. √2g [H13/2 - Ha3/2] (2/3) Cd × L.√2g [H12 - Ha2] (2/3) Cd × L. √2g [H15/2 - Ha5/2] (2/3) Cd × L.√2g [H1 - Ha] (2/3) Cd × L. √2g [H13/2 - Ha3/2] ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS