Electrical Machines Voltage regulation of transformer is given by (V2 - E2) / V2 (V2 - E2) / E2 (E2 - V2) / V2 (E2 - V2) / E2 (V2 - E2) / V2 (V2 - E2) / E2 (E2 - V2) / V2 (E2 - V2) / E2 ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines Under which of the following conditions is a dc motor provided with compensating winding used ? 1. Wide range of speed control above normal 2. Wide range of steady load variation with no speed control 3.Wide range of rapid variation in load Select the correct answer using the codes given below : Codes : 2 and 3 1 and 2 1, 2 and 3 1 and 3 2 and 3 1 and 2 1, 2 and 3 1 and 3 ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines The introduction of interpoles in between the main poles improves the performance of a dc machine, because the flux waveform is improved with reduction in harmonics the interpoles produce additional flux to augment the developed torque the inequality of air-gap flux on the top and bottom halves of the armature is removed a counter-emf is induced in the coil undergoing commutation the flux waveform is improved with reduction in harmonics the interpoles produce additional flux to augment the developed torque the inequality of air-gap flux on the top and bottom halves of the armature is removed a counter-emf is induced in the coil undergoing commutation ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines Direction of the current in the compensating winding is________ to the direction of current in the armature conductors? same exactly opposite None of these either of these same exactly opposite None of these either of these ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines A 400 V, 50 Hz, 30 Hp, three phase IM is drawing 50 A current at 0.8 p.f lagging. The stator and rotor copper losses are 1.5 KW and 900 W respectively. The friction and windage losses are 1050 W and core losses are 1200 W. The air gap power of the motor will be 23.06 kW. 24.11 kW. 25 kW. 26.21 kW. 23.06 kW. 24.11 kW. 25 kW. 26.21 kW. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines If B is flux density, l the length of the conductor and v the velocity of the conductor, then emf is given by Bl2v2. Bl2v. Blv. Blv2. Bl2v2. Bl2v. Blv. Blv2. ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS