Electrical Machines Voltage regulation of transformer is given by (E2 - V2) / E2 (E2 - V2) / V2 (V2 - E2) / E2 (V2 - E2) / V2 (E2 - V2) / E2 (E2 - V2) / V2 (V2 - E2) / E2 (V2 - E2) / V2 ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines A 500 V, 55 kVA single phase alternator has an effective resistance of 0.5 Ω. An excitation current of 10 A produces 200 A armature current on short circuit and an emf of 450 V on per circuit. The synchronous reactance will be 2.74 Ω. 25.564 Ω. 2.241 Ω. 2.781 Ω. 2.74 Ω. 25.564 Ω. 2.241 Ω. 2.781 Ω. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines In a synchronous motor torque or load angle δ ------------- with increase in load remains unaffected increases decreases None of these remains unaffected increases decreases None of these ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines The current drawn by a 220 V DC series motor of armature resistance 0.5Ω and back back emf 200 V is 40 A. 440 A. 44 A. 400 A. 40 A. 440 A. 44 A. 400 A. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines What is the mechanical power developed by a DC series motor is maximum? Back emf is equal to zero. Back emf is equal to half the applied voltage. None of above. Back emf is equal to applied voltage. Back emf is equal to zero. Back emf is equal to half the applied voltage. None of above. Back emf is equal to applied voltage. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines Maximum power developed by a synchronous motor depends on supply voltage, load angle and excitation excitation and load angle supply voltage and excitation supply voltage and load angle supply voltage, load angle and excitation excitation and load angle supply voltage and excitation supply voltage and load angle ANSWER DOWNLOAD EXAMIANS APP
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