Applied Mechanics and Graphic Statics Varingon’s theorem of moment’s states Algebraic sum of the moments of the forces about any point in their plane, is equal to the moment of their resultant about that point Arithmetical sum of the moments of the forces about any point in their plane, is equal to the moment of their resultant about that point Algebraic sum of the moments of two forces about any point, is equal to the moment of their resultant about that point Arithmetical sum of the moments of two forces about any point, is equal to the moments of their resultant about that point Algebraic sum of the moments of the forces about any point in their plane, is equal to the moment of their resultant about that point Arithmetical sum of the moments of the forces about any point in their plane, is equal to the moment of their resultant about that point Algebraic sum of the moments of two forces about any point, is equal to the moment of their resultant about that point Arithmetical sum of the moments of two forces about any point, is equal to the moments of their resultant about that point ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The C.G. of a right circular cone lies on its axis of symmetry at a height of h/3 h/4 h/5 h/2 h/3 h/4 h/5 h/2 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics At the instantaneous center, the velocity of the moving lamina at any instant is Minimum Maximum Varying Zero Minimum Maximum Varying Zero ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If y is force and x is velocity, then dimensions of —=r are dx2 M’L-‘T0 M’L-‘T1 M’^T’ M2L’T3 M’L-‘T0 M’L-‘T1 M’^T’ M2L’T3 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A particle moves with a velocity of 2 m/sec in a straight line with a negative acceleration of 0.1 m/sec2. Time required to traverse a distance of 1.5 m, is 40 sec 15 sec 20 sec 30 sec 40 sec 15 sec 20 sec 30 sec ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics For a simple pendulum, time period for a beat, is π √(g/2l) π √(l/2g) π √(l/g) π √(2l/g) π √(g/2l) π √(l/2g) π √(l/g) π √(2l/g) ANSWER DOWNLOAD EXAMIANS APP
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