Engineering Mechanics Two balls of equal mass and of perfectly elastic material are lying on the floor. One of the balls with velocity ‘v’ is made to strike the second ball. Both the balls after impact will move with a velocity v/2 v v/8 v/4 v/2 v v/8 v/4 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics During elastic impact, the relative velocity of the two bodies after impact is __________ the relative velocity of the two bodies before impact. Equal to Less than Equal and opposite to Greater than Equal to Less than Equal and opposite to Greater than ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The acceleration of a particle moving with simple harmonic motion, at any instant is given by ω2.y ω2/y ω.y ω3.y ω2.y ω2/y ω.y ω3.y ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The Cartesian equation of trajectory is (where u = Velocity of projection, α = Angle of projection, and x, y = Co-ordinates of any point on the trajectory after t seconds.) y = (gx²/2u² cos²α) + x. tanα y = x. tanα + (gx²/2u² cos²α) y = (gx²/2u² cos²α) - x. tanα y = x. tanα - (gx²/2u² cos²α) y = (gx²/2u² cos²α) + x. tanα y = x. tanα + (gx²/2u² cos²α) y = (gx²/2u² cos²α) - x. tanα y = x. tanα - (gx²/2u² cos²α) ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The resolved part of the resultant of two forces inclined at an angle 'θ' in a given direction is equal to The algebraic sum of the resolved parts of the forces in the given direction The difference of the forces multiplied by the cosine of θ The sum of the resolved parts of the forces in the given direction The sum of the forces multiplied by the sine of θ The algebraic sum of the resolved parts of the forces in the given direction The difference of the forces multiplied by the cosine of θ The sum of the resolved parts of the forces in the given direction The sum of the forces multiplied by the sine of θ ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The equivalent length of a simple pendulum which gives the same frequency as compound pendulum is h²/(kG² + h²) (kG² + h²)/h (kG² + h²)/h² h/(kG² + h²) h²/(kG² + h²) (kG² + h²)/h (kG² + h²)/h² h/(kG² + h²) ANSWER DOWNLOAD EXAMIANS APP
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