Concrete Technology and Design of Concrete Structures To minimize the effect of differential settlement, the area of a footing should be designed for Dead load + live load Live load + fraction of dead load Dead load + fraction of live load Dead load only Dead load + live load Live load + fraction of dead load Dead load + fraction of live load Dead load only ANSWER DOWNLOAD EXAMIANS APP
Concrete Technology and Design of Concrete Structures To determine the modulus of rupture, the size of test specimen used is 150 x150 x500 mm 150 x150 x700 mm 100 x100 x500 mm 100 x100 x700 mm 150 x150 x500 mm 150 x150 x700 mm 100 x100 x500 mm 100 x100 x700 mm ANSWER DOWNLOAD EXAMIANS APP
Concrete Technology and Design of Concrete Structures Ratio of permissible stress in direct compression and bending compression is between 1.5 and 2.0 less than 1 between 1 and 1.5 greater than 2 between 1.5 and 2.0 less than 1 between 1 and 1.5 greater than 2 ANSWER DOWNLOAD EXAMIANS APP
Concrete Technology and Design of Concrete Structures The maximum value of hoop compression in a dome is given by (where, w = load per unit area of surface of dome R = radius of curvature d = thickness of dome) wR/d wR/2d wR / 4d 2wR/d wR/d wR/2d wR / 4d 2wR/d ANSWER DOWNLOAD EXAMIANS APP
Concrete Technology and Design of Concrete Structures Sinking of an intermediate support of a continuous beami) reduces the negative moment at supportii) increases the negative moment at supportiii) reduces the positive moment at center of spaniv) increases the positive moment at center of span The correct answer is (ii) and (iii) (i) and (iii) (i) and (iv) (ii) and (iv) (ii) and (iii) (i) and (iii) (i) and (iv) (ii) and (iv) ANSWER DOWNLOAD EXAMIANS APP
Concrete Technology and Design of Concrete Structures The relation between modulus of rupture fcr, splitting strength fcs and direct tensile strength fcl is given by fc5>fcr>fC fcr tcr – rcs = tct fcr>fcs>fc. fc5>fcr>fC fcr tcr – rcs = tct fcr>fcs>fc. ANSWER DOWNLOAD EXAMIANS APP
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