Theory of Machine Throw of a cam is the maximum distance of the follower from Pitch circle Prime circle Base circle Root circle Pitch circle Prime circle Base circle Root circle ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The two links OA and OB are connected by a pin joint at O. If the link OA turns with angular velocity ω₁ rad/s in the clockwise direction and the link OB turns with angular velocity ω₂ rad/s in the anticlockwise direction, then the rubbing velocity at the pin joint O is (where r = Radius of the pin at O) (ω₁ - ω₂) 2r ω₁.ω₂.r (ω₁ - ω₂) r (ω₁ + ω₂) r (ω₁ - ω₂) 2r ω₁.ω₂.r (ω₁ - ω₂) r (ω₁ + ω₂) r ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine There are six gears A, B, C, D, E and F in a compound train. The numbers of teeth in the gears are 20, 60, 30, 80, 25 and 75 respectively. The ratio of angular speeds of the driven (F) to the driver (A) of the drive is 1/24 1/8 4/15 12 1/24 1/8 4/15 12 ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine A shaft has an attached disc at the centre of its length. The disc has its centre of gravity located at a distance of 2 mm from the axis of the shaft. When the shaft is allowed to vibrate in its natural bow-shaped mode, it has a frequency of vibration of 10 rad/s. When the shaft is rotated at 300 r.p.m., it will whirl with a radius of 2 mm 2.22 mm 2.50 mm 3.0 mm 2 mm 2.22 mm 2.50 mm 3.0 mm ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine A disturbing mass m₁ attached to the rotating shaft may be balanced by a single mass m₂ attached in the same plane of rotation as that of m₁, such that (where r₁ and r₂ are the radii of rotation of m₁ and m₂ respectively) m₁ r₂ = m₂ r₁ m₁ m₂ = r₁ r₂ m₁ r₁ = m₂ r₂ None of these m₁ r₂ = m₂ r₁ m₁ m₂ = r₁ r₂ m₁ r₁ = m₂ r₂ None of these ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine Two heavy rotating masses are connected by shafts of lengths l₁, l₂ and l₃ and the corresponding diameters are d₁, d₂ and d₃. This system is reduced to a torsionally equivalent system having uniform diameter d = d₁ of the shaft. The equivalent length of the shaft is l = l₁ + l₂.(d₁/d₂)³ + l₂.(d₁/d₃)³ l₁ + l₂ + l₃ (l₁ + l₂ + l₃)/3 l = l₁ + l₂.(d₁/d₂)⁴ + l₃.(d₁/d₃)⁴ l = l₁ + l₂.(d₁/d₂)³ + l₂.(d₁/d₃)³ l₁ + l₂ + l₃ (l₁ + l₂ + l₃)/3 l = l₁ + l₂.(d₁/d₂)⁴ + l₃.(d₁/d₃)⁴ ANSWER DOWNLOAD EXAMIANS APP
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