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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M
Three numbers are in the ratio 3:4:5 and their L.C.M is 2400. Their H.C.F is:

80
200
120
40

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Problems on H.C.F and L.C.M
Product of two co-prime numbers is 117. Their L.C.M should be:

117
1
Cannot be calculated
F
equal to their H.

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The least number which when divided by 5,6,7 And 8 leaves a remainder 3, but when divided by 9 leaves no remainder, is :

1677
2523
3363
1683

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Problems on H.C.F and L.C.M
The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18 is:

364
777
1045
1745

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

L.C.M. of 6, 9, 15 and 18 is 90.Let required number be 90k + 4, which is multiple of 7.Least value of k for which (90k + 4) is divisible by 7 is k = 4.Required number = (90 x 4) + 4 = 364.

Problems on H.C.F and L.C.M
The largest four-digit number which when divided by 4, 7 or 13 leaves a remainder of 3 in each case,is :

9893
8739
9831
9834

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The greatest number of four digits that have 144 for their HCF is?

9935
9936
9903
9930

ANSWER DOWNLOAD EXAMIANS APP
MORE MCQ ON Problems on H.C.F and L.C.M

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