Engineering Mechanics The velocity ratio for the third system of pulleys is n n² 2n 2n - 1 n n² 2n 2n - 1 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The rate of change of momentum is directly proportional to the impressed force, and takes place in the same direction in which the force acts. This statement is known as Newton's second law of motion None of these Newton's third law of motion Newton's first law of motion Newton's second law of motion None of these Newton's third law of motion Newton's first law of motion ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics A screw jack used for lifting the loads is A reversible machine An ideal machine None of these A non-reversible machine A reversible machine An ideal machine None of these A non-reversible machine ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Mass moment of inertia of a uniform thin rod of mass M and length (l) about its mid-point and perpendicular to its length is (3/4) Ml² (1/12) Ml² (2/3) Ml² (1/3) Ml² (3/4) Ml² (1/12) Ml² (2/3) Ml² (1/3) Ml² ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics According to the law of moments, if a number of coplanar forces acting on a particle are in equilibrium, then The algebraic sum of their moments about any point in their plane is zero The algebraic sum of their moments about any point is equal to the moment of their resultant force about the same point Their algebraic sum is zero Their lines of action are at equal distances The algebraic sum of their moments about any point in their plane is zero The algebraic sum of their moments about any point is equal to the moment of their resultant force about the same point Their algebraic sum is zero Their lines of action are at equal distances ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The Cartesian equation of trajectory is (where u = Velocity of projection, α = Angle of projection, and x, y = Co-ordinates of any point on the trajectory after t seconds.) y = (gx²/2u² cos²α) + x. tanα y = x. tanα - (gx²/2u² cos²α) y = x. tanα + (gx²/2u² cos²α) y = (gx²/2u² cos²α) - x. tanα y = (gx²/2u² cos²α) + x. tanα y = x. tanα - (gx²/2u² cos²α) y = x. tanα + (gx²/2u² cos²α) y = (gx²/2u² cos²α) - x. tanα ANSWER DOWNLOAD EXAMIANS APP
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