Engineering Mechanics The velocity of a body on reaching the ground from a height h, is √(gh) √(2gh) 2g.√h 2.√(gh) √(gh) √(2gh) 2g.√h 2.√(gh) ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The skidding away of the vehicle on a level circular path can be avoided if the force of friction between the wheels and the ground is __________ the centrifugal force. Less than None of these Equal to Greater than Less than None of these Equal to Greater than ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Moment of inertia of a circular section about an axis perpendicular to the section is πd4/32 πd3/16 πd3/32 πd4/64 πd4/32 πd3/16 πd3/32 πd4/64 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The velocity ratio of a differential pulley block with D and d as the diameters of larger and smaller pulley, is 2D/(D - d) D/(D + d) D/(D - d) 2D/(D + d) 2D/(D - d) D/(D + d) D/(D - d) 2D/(D + d) ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics A semicircular disc rests on a horizontal surface with its top flat surface horizontal and circular portion touching down. The coefficient of friction between semi circular disc and horizontal surface is µ. This disc is to be pulled by a horizontal force applied at one edge and it always remains horizontal. When the disc is about to start moving, its top horizontal force will Remain horizontal Slant up towards direction of pull Slant down towards direction of pull None of these Remain horizontal Slant up towards direction of pull Slant down towards direction of pull None of these ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.) IP = IG - Ah2 IP = Ah2 / IG IP = IG / Ah2 IP = IG + Ah2 IP = IG - Ah2 IP = Ah2 / IG IP = IG / Ah2 IP = IG + Ah2 ANSWER DOWNLOAD EXAMIANS APP
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