Engineering Mechanics The velocity of a body on reaching the ground from a height h, is 2.√(gh) √(2gh) 2g.√h √(gh) 2.√(gh) √(2gh) 2g.√h √(gh) ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics A lead ball with a certain velocity is made to strike a wall, it falls down, but rubber ball of same mass and with same velocity strikes the same wall, it rebounds. Select the correct reason from the following: The change in momentum suffered by rubber ball is less than the lead ball The change in momentum suffered by rubber ball is more than the lead ball Both the balls undergo an equal change in momentum None of these The change in momentum suffered by rubber ball is less than the lead ball The change in momentum suffered by rubber ball is more than the lead ball Both the balls undergo an equal change in momentum None of these ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The moment of inertia of a thin disc of mass ‘m’ and radius ‘r’, about an axis through its center of gravity and perpendicular to the plane of the disc is mr²/2 mr²/6 mr²/4 mr²/8 mr²/2 mr²/6 mr²/4 mr²/8 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.) IP = IG / Ah2 IP = IG - Ah2 IP = Ah2 / IG IP = IG + Ah2 IP = IG / Ah2 IP = IG - Ah2 IP = Ah2 / IG IP = IG + Ah2 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Moment of inertia of a triangular section of base (b) and height (h) about an axis passing through its C.G. and parallel to the base, is bh3/4 bh3/12 bh3/36 bh3/8 bh3/4 bh3/12 bh3/36 bh3/8 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The centre of percussion is below the centre of gravity of the body and is at a distance equal to kG2/h h2/kG h/kG h × kG kG2/h h2/kG h/kG h × kG ANSWER DOWNLOAD EXAMIANS APP
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