Applied Mechanics and Graphic Statics The unit of moments in M.K.S system, is kg/sec kg.m kg/m2 kg/sec2 kg/sec kg.m kg/m2 kg/sec2 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If two bodies of masses M1 and M2(M1 > M2) are connected by alight inextensible string passing over a smooth pulley, the tension in the string, will be given by T = g(M1 - M2)/(M1 + M2) T = g(M2 - M1)/(M1 + M2) T = g(M1 + M2)/(M1 × M2) T = g(M2 + M1)/(M2 - M1) T = g(M1 - M2)/(M1 + M2) T = g(M2 - M1)/(M1 + M2) T = g(M1 + M2)/(M1 × M2) T = g(M2 + M1)/(M2 - M1) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The maximum frictional force which comes into play, when a body just begins to slide over the surface of a another body, is known Sliding friction Limiting friction Rolling friction None of these Sliding friction Limiting friction Rolling friction None of these ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A ball is dropped from a height of 2.25 m on a smooth floor and rises to a height of 1.00 m after the bounce. The coefficient of restitution between the ball and the floor is 0.57 0.67 0.44 0.33 0.57 0.67 0.44 0.33 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics ‘u₁’ and ‘u₂’ are the velocities of approach of two moving bodies in the same direction and their corresponding velocities of separation are ‘v₁’ and ‘v₂’. As per Newton's law of collision of elastic bodies, the coefficient of restitution (e) is given by e = v₁ - v₂/u₂ - u₁ e = v₂ - v₁/u₁ - u₂ e = u₂ - u₁/v₁ - v₂ e = v₁ - v₂/u₂ + u₁ e = v₁ - v₂/u₂ - u₁ e = v₂ - v₁/u₁ - u₂ e = u₂ - u₁/v₁ - v₂ e = v₁ - v₂/u₂ + u₁ ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A particle is executing simple harmonic motion in a line 1.0 m long. If the time of one complete vibration is 1 sec, then the maximum velocity of the particle is 6.28 m/sec 1.57 m/sec 1.00 m/sec 3.14 m/sec 6.28 m/sec 1.57 m/sec 1.00 m/sec 3.14 m/sec ANSWER DOWNLOAD EXAMIANS APP
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