Control Systems The unit impulse response of second order system is 1/6 * e-0.8t sin(0.6t). THen the natural frequency is 0.6 rad/s 1 rad/s 0.8 rad/s 2 rad/s 0.6 rad/s 1 rad/s 0.8 rad/s 2 rad/s ANSWER DOWNLOAD EXAMIANS APP
Control Systems Lowest critical frequency is due to pole and it may be present at the origin or nearer to the origin, then the type of network is RC. RL. LC. Any of the above. RC. RL. LC. Any of the above. ANSWER DOWNLOAD EXAMIANS APP
Control Systems If the bandwidth of the system is very large, the system response is None of these slower faster independent of bandwidth None of these slower faster independent of bandwidth ANSWER DOWNLOAD EXAMIANS APP
Control Systems The impulse response of a system is c(t) = -te-t + 2 e-t (t>0). Its closed loop transfer function is (2s+1)/s² (2s+2)/(s+1)² (2s+2)/s² (2s+1)/(s+1)² (2s+1)/s² (2s+2)/(s+1)² (2s+2)/s² (2s+1)/(s+1)² ANSWER DOWNLOAD EXAMIANS APP
Control Systems The low frequency and high frequency asymptotes of Bode magnitude plot are respectively -60dB/decade and -40dB/decade. What is the type of the system? TYPE III TYPE II TYPE 0 TYPE I TYPE III TYPE II TYPE 0 TYPE I ANSWER DOWNLOAD EXAMIANS APP
Control Systems Consider a network function H(s) = 2(s+3)/{(s+2)(s+4)}. What is the steady state response due to step input? 3/4 4/3 1 1/2 3/4 4/3 1 1/2 ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS