C Programming The type of the controlling expression of a switch statement cannot be of the type ........ short int long char float short int long char float ANSWER DOWNLOAD EXAMIANS APP
C Programming What will be the output of the program?#include#define int char void main(){ int i = 65; printf("sizeof(i)=%d", sizeof(i));} sizeof(i)=1 Compiler Error sizeof(i)=2 None of These sizeof(i)=1 Compiler Error sizeof(i)=2 None of These ANSWER DOWNLOAD EXAMIANS APP
C Programming Determine Output:void main(){ static int var = 5; printf("%d ", var--); if(var) main();} Infinite Loop None of These 5 4 3 2 1 5 5 5 5 5 Infinite Loop None of These 5 4 3 2 1 5 5 5 5 5 ANSWER DOWNLOAD EXAMIANS APP
C Programming Determine output:void main(){ int i=0, j=1, k=2, m; m = i++ || j++ || k++; printf("%d %d %d %d", m, i, j, k);} 0 1 2 2 1 1 2 2 0 1 2 3 1 1 2 3 None of these 0 1 2 2 1 1 2 2 0 1 2 3 1 1 2 3 None of these ANSWER DOWNLOAD EXAMIANS APP
C Programming Determine Output:void main(){ int i=1; while(i<=5) { printf("%d", i); if(i>2) goto here; i++; }}fun(){ here: printf("PP");} 12PP 12PP345 None of These Compiler Error 12PP 12PP345 None of These Compiler Error ANSWER DOWNLOAD EXAMIANS APP
C Programming What's wrong in the following statement, provided k is a variable of type int?for(k = 2, k <=12, k++) The variable k can’t be initialized. The commas should be semicolons. The increment should always be ++k . The variable must always be the letter i when using a for loop. There should be a semicolon at the end of the statement. The variable k can’t be initialized. The commas should be semicolons. The increment should always be ++k . The variable must always be the letter i when using a for loop. There should be a semicolon at the end of the statement. ANSWER DOWNLOAD EXAMIANS APP
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