C Programming What will be the output of the given program?#includevoid main(){ int i=10; printf("i=%d", i); { int i=20; printf("i=%d", i); i++; printf("i=%d", i); } printf("i=%d", i);} 10 20 21 10 10 20 21 21 10 10 11 11 10 20 21 20 10 20 21 10 10 20 21 21 10 10 11 11 10 20 21 20 ANSWER DOWNLOAD EXAMIANS APP
C Programming Choose the best answer.Prior to using a pointer variable None of these. It should be initialized. It should be both declared and initialized. It should be declared. None of these. It should be initialized. It should be both declared and initialized. It should be declared. ANSWER DOWNLOAD EXAMIANS APP
C Programming Determine Output:void main(){ char not; not = !2; printf("%d", not);} 0 None of These 2 Garbage Value 0 None of These 2 Garbage Value ANSWER DOWNLOAD EXAMIANS APP
C Programming What will be the following code's output if choice = 'R'?switch(choice){ case 'R' : printf("RED"); case 'W' : printf("WHITE"); case 'B' : printf("BLUE"); default : printf("ERROR");break;} RED RED WHITE BLUE ERROR RED WHITE BLUE RED ERROR ERROR RED RED WHITE BLUE ERROR RED WHITE BLUE RED ERROR ERROR ANSWER DOWNLOAD EXAMIANS APP
C Programming What will be the output of the following program? #include\ int main(){ extern int i; i = 20; printf("%ld ", sizeof(i)); return 0; } 2 Depends on the Compiler 4 Linker Error : Undefined symbol 'i' 2 Depends on the Compiler 4 Linker Error : Undefined symbol 'i' ANSWER DOWNLOAD EXAMIANS APP
C Programming The statement int **a; is legal but meaningless is syntactically and semantically correct is illegal None of these. is legal but meaningless is syntactically and semantically correct is illegal None of these. ANSWER DOWNLOAD EXAMIANS APP
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