SSC JE Electrical 2019 with solution SET-2
The 2’s complement of 1010101 is

0101010
1110011
0101011
1101010

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SSC JE Electrical 2019 with solution SET-2
Observe the given figure. The maximum power to the load resistor is when Ri is  =?

Ri/2
RL
2Ri
4Ri

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SSC JE Electrical 2019 with solution SET-2
IL = Load Current, then the relation between these currents for a DC series generator is

IL ÷ Ise ÷ Ia
IL = Ise = Ia
IL = Ise + Ia
IL ÷ Ise = Ia

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