Refrigeration and Air Conditioning The temperature of air recorded by a thermometer, when its bulb is surrounded by a wet cloth exposed to the air, is called Dry bulb temperature None of these Dew point temperature Wet bulb temperature Dry bulb temperature None of these Dew point temperature Wet bulb temperature ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning An important characteristic of absorption system of refrigeration is quiet operation very little power consumption noisy operation cooling below 0°C quiet operation very little power consumption noisy operation cooling below 0°C ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning During sensible heating of air _________ decreases. Wet bulb temperature Specific humidity Relative humidity Dry bulb temperature Wet bulb temperature Specific humidity Relative humidity Dry bulb temperature ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning In S.J. unit, one ton of refrigeration is equal to 21 kJ/ min 210 kJ/ min 420 kJ/ min 840 kJ/ min 21 kJ/ min 210 kJ/ min 420 kJ/ min 840 kJ/ min ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning The coefficient of performance of Electrolux refrigerator is the ratio of Heat absorbed by the evaporator to the heat supplied by the gas burner Heat supplied by the gas burner minus the heat absorbed by the evaporator to the heat supplied by the gas burner Heat absorbed by the evaporator minus the heat supplied by the gas burner to the heat absorbed by the evaporator Heat supplied by the gas burner to the heat absorbed by the evaporator Heat absorbed by the evaporator to the heat supplied by the gas burner Heat supplied by the gas burner minus the heat absorbed by the evaporator to the heat supplied by the gas burner Heat absorbed by the evaporator minus the heat supplied by the gas burner to the heat absorbed by the evaporator Heat supplied by the gas burner to the heat absorbed by the evaporator ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning The bypass factor (B. P. F.) in case of sensible heating of air is (Where td₁ = Dry bulb temperature of air entering the heating coil, td₂ = Dry bulb temperature of air leaving the heating coil, and td₃ = Dry bulb temperature of heating coil) (td₂ - td₃)/(td₃ - td₁) (td₃ - td₁)/(td₂ - td₃) (td₃ - td₂)/(td₃ - td₁) (td₃ - td₁)/(td₃ - td₂) (td₂ - td₃)/(td₃ - td₁) (td₃ - td₁)/(td₂ - td₃) (td₃ - td₂)/(td₃ - td₁) (td₃ - td₁)/(td₃ - td₂) ANSWER DOWNLOAD EXAMIANS APP
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