Electrical Machines The synchronous speed of an induction motor will be increased by increasing of frequency. speed can not be increased. decreasing of frequency. increasing number of poles. increasing of frequency. speed can not be increased. decreasing of frequency. increasing number of poles. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines In a 3 - Φ IM with line frequency f1 and winding factor kw1 and kw2 for stator and rotor respectively the ratio of per phase stator winding emf E1 to per phase rotor winding emf E2 at standstill is given by E1 / E2 = f1kw1 / f2kw2. E1 / E2 = N1 / N2. E1 / E2 = N1kw1 / N2kw2. E1 / E2 = 1. E1 / E2 = f1kw1 / f2kw2. E1 / E2 = N1 / N2. E1 / E2 = N1kw1 / N2kw2. E1 / E2 = 1. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines For an ideal transformer the winding should have minimum resistance on primary side and maximum resistance on secondary side maximum resistance on primary side and least resistance on secondary side equal resistance on primary and secondary side no ohmic resistance on either side minimum resistance on primary side and maximum resistance on secondary side maximum resistance on primary side and least resistance on secondary side equal resistance on primary and secondary side no ohmic resistance on either side ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines Voltage across the open circuited field termninals of a synchorous machine under slip test is DC. AC of supply frequency. DC of slip frequency. A modulated supply frequency AC voltage with slip frequency envelop. DC. AC of supply frequency. DC of slip frequency. A modulated supply frequency AC voltage with slip frequency envelop. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines A 400 V, 50 Hz, 30 Hp, three phase IM is drawing 50 A current at 0.8 p.f lagging. The stator and rotor copper losses are 1.5 KW and 900 W respectively. The friction and windage losses are 1050 W and core losses are 1200 W. The air gap power of the motor will be 26.21 kW. 23.06 kW. 24.11 kW. 25 kW. 26.21 kW. 23.06 kW. 24.11 kW. 25 kW. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines A 500 V, 120 KW, 50 Hz, star connected synchronous motor operating at 0.8 power factor leading has full load efficiency of 91%. The armature resistance is equal to 0.08Ω. The magnitude of armature current is nearly equal to 173 A. 190 A. 127 A. 240 A. 173 A. 190 A. 127 A. 240 A. ANSWER DOWNLOAD EXAMIANS APP
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