Hydraulics and Fluid Mechanics in ME The surface tension of mercury at normal temperature is __________ that of water. Lower than None of these Same as Higher than Lower than None of these Same as Higher than ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME An orifice is said to be large, if The velocity of flow is large The available head of liquid is more than 5 times the height of orifice The size of orifice is large The available head of liquid is less than 5 times the height of orifice The velocity of flow is large The available head of liquid is more than 5 times the height of orifice The size of orifice is large The available head of liquid is less than 5 times the height of orifice ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME Newton's law of viscosity is a relationship between Shear stress and rate of shear strain Pressure, velocity and temperature Shear stress and velocity Rate of shear strain and temperature Shear stress and rate of shear strain Pressure, velocity and temperature Shear stress and velocity Rate of shear strain and temperature ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The diameter of the nozzle (d) for maximum transmission of power is given by (where D = Diameter of pipe, f = Darcy’s coefficient of friction for pipe, and l = Length of pipe) d = (D⁵/8fl)1/3 d = (D⁵/8fl)1/4 d = (D⁵/8fl)1/2 d = (D⁵/8fl)1/5 d = (D⁵/8fl)1/3 d = (D⁵/8fl)1/4 d = (D⁵/8fl)1/2 d = (D⁵/8fl)1/5 ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The discharge in an open channel corresponding to critical depth is Maximum Zero None of these Minimum Maximum Zero None of these Minimum ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME According to Francis formula, the discharge over a rectangular weir is (where n = Number of end contractions) (2/3) × Cd (L - nH) × √(2g) × H² (2/3) × Cd (L - 0.1nH) × √(2g) × H3/2 (2/3) × Cd (L - nH) × √(2g) × H5/2 (2/3) × Cd (L - nH) × √(2gh) (2/3) × Cd (L - nH) × √(2g) × H² (2/3) × Cd (L - 0.1nH) × √(2g) × H3/2 (2/3) × Cd (L - nH) × √(2g) × H5/2 (2/3) × Cd (L - nH) × √(2gh) ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS