Electrical Machines The speed regulation of a DC motor is given as NnL/NfL. (NfL − NnL)/NnL. NnL − NfL. (NnL − NfL)/NfL. NnL/NfL. (NfL − NnL)/NnL. NnL − NfL. (NnL − NfL)/NfL. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines In a seperately excited DC Motor if field current is increased, it will Reduce armature heating. Increase speed Reduce starting torque. Increase acceleration duration. Reduce armature heating. Increase speed Reduce starting torque. Increase acceleration duration. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines If Pi and Pc represent core and full load copper loss respectively, the maximum KVA delivered to load corresponding to maximum efficiency is equal to rated KVA is Pi/Pc (Pi/Pc)2 √(Pi/Pc) Pc/Pi Pi/Pc (Pi/Pc)2 √(Pi/Pc) Pc/Pi ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines The synchronous speed of an induction motor will be increased by increasing of frequency. speed can not be increased. decreasing of frequency. increasing number of poles. increasing of frequency. speed can not be increased. decreasing of frequency. increasing number of poles. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines The mechanical power is developed by a DC motor is maximum when back emf is equal to half of applied voltage. back emf is equal to twice of applied voltage. back emf is equal to applied voltage. none of above. back emf is equal to half of applied voltage. back emf is equal to twice of applied voltage. back emf is equal to applied voltage. none of above. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines Air core transformer as compared to iron core transformer, has less magnetic core loss. more copper loss. no magnetic core loss. more magnetic core loss. less magnetic core loss. more copper loss. no magnetic core loss. more magnetic core loss. ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS