Applied Mechanics and Graphic Statics The shape of a suspended cable under its own weight, is Circular Parabolic Elliptical Catenary Circular Parabolic Elliptical Catenary ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics On a ladder resting on a rough ground and leaning against a smooth vertical wall, the force of friction acts Upwards at its upper end Downwards at its upper end Zero at its upper end Perpendicular to the wall at its upper end Upwards at its upper end Downwards at its upper end Zero at its upper end Perpendicular to the wall at its upper end ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The dimensions of centrifugal force are M’L’T1 M’L-‘T2 M1 L2 T2 M’L’T2 M’L’T1 M’L-‘T2 M1 L2 T2 M’L’T2 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics Kinetic friction may be defined as Angle between normal reaction and resultant of normal reaction and limiting friction Friction force acting when the body is in motion Friction force acting when the body is just about to move Ratio of limiting friction and normal reaction Angle between normal reaction and resultant of normal reaction and limiting friction Friction force acting when the body is in motion Friction force acting when the body is just about to move Ratio of limiting friction and normal reaction ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If two forces each equal to ‘T’ in magnitude act at right angles, their effect may be neutralized by a third force acting along their bisector in opposite direction whose magnitude will be 3 T 2 T 1/2 T √2 T 3 T 2 T 1/2 T √2 T ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A square hole is punched out of a circular lamina, the diagonal of the square being the radius of the circle. If ‘r’ is the radius of the circle, the C.G. of the remainder from the corner of the square on the circumference will be [r (π - 0.25)]/(π - 0.5) [r (π + 0.25)]/(π - 0.5) [r (π + 0.25)]/(π + 0.5) [r (π - 0.5)]/(π + 0.25) [r (π - 0.25)]/(π - 0.5) [r (π + 0.25)]/(π - 0.5) [r (π + 0.25)]/(π + 0.5) [r (π - 0.5)]/(π + 0.25) ANSWER DOWNLOAD EXAMIANS APP
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