Chemical Engineering Thermodynamics The second law of thermodynamics states that The total energy of system and surrounding remains the same The energy change of a system undergoing any reversible process is zero None of these It is not possible to transfer heat from a lower temperature to a higher temperature The total energy of system and surrounding remains the same The energy change of a system undergoing any reversible process is zero None of these It is not possible to transfer heat from a lower temperature to a higher temperature ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics Which law of the thermodynamics provids basis for measuring the thermodynamic property? First law Zeroth law Third law Second law First law Zeroth law Third law Second law ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics Out of the following refrigeration cycles, which one has maximum COP? Vapor compression with a reversible expansion engine Ordinary vapor compression cycle Air cycle Carnot cycle Vapor compression with a reversible expansion engine Ordinary vapor compression cycle Air cycle Carnot cycle ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics Solubility of a substance which dissolves with an increase in volume and liberation of heat will be favoured by the High pressure and low temperature High pressure and high temperature Low pressure and low temperature Low pressure and high temperature High pressure and low temperature High pressure and high temperature Low pressure and low temperature Low pressure and high temperature ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics On a P-V diagram of an ideal gas, suppose a reversible adiabatic line intersects a reversible isothermal line at point A. Then at a point A, the slope of the reversible adiabatic line (∂P/∂V)S and the slope of the reversible isothermal line (∂P/∂V)T are related as (where, y = Cp/Cv) ) (∂P/∂V)S = y(∂P/∂V)T (∂P/∂V)S = [(∂P/∂V)T]Y (∂P/∂V)S = (∂P/∂V)T (∂P/∂V)S = 1/y(∂P/∂V)T (∂P/∂V)S = y(∂P/∂V)T (∂P/∂V)S = [(∂P/∂V)T]Y (∂P/∂V)S = (∂P/∂V)T (∂P/∂V)S = 1/y(∂P/∂V)T ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics A gas can be liquified by pressure alone only, when its temperature is __________ its critical temperature. Less than or equal to Equal to or higher than More than Less than Less than or equal to Equal to or higher than More than Less than ANSWER DOWNLOAD EXAMIANS APP
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