Applied Mechanics and Graphic Statics The resultant of two forces acting at right angles is √34 kg and acting at 60° is 70 kg. The forces are 1 kg and 4 kg 2 kg and 3 kg √3 kg and √5 kg 3 kg and 5 kg 1 kg and 4 kg 2 kg and 3 kg √3 kg and √5 kg 3 kg and 5 kg ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A ball moving on a smooth horizontal table hits a rough vertical wall, the coefficient of restitution between ball and wall being 1/3. The ball rebounds at the same angle. The fraction of its kinetic energy lost is 44052 43833 43864 43839 44052 43833 43864 43839 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A satellite moves in its orbit around the earth due to Centripetal force None of these Centrifugal force Gravitational force Centripetal force None of these Centrifugal force Gravitational force ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics Two shots fired simultaneously from the top and bottom of a vertical tower with elevations of 30° and 45° respectively strike a target simultaneously. If horizontal distance of the target from the tower is 1000 m, the height of the tower is 400 m 350 m 375 m 425 m 400 m 350 m 375 m 425 m ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The following is not a law of static friction: The force of friction always acts in a direction opposite to that in which the body tends to move The force of friction is dependent upon the area of contact The magnitude of the limiting friction bears a constant ratio to the normal reaction between two surfaces The force of friction depends upon the roughness of the surface The force of friction always acts in a direction opposite to that in which the body tends to move The force of friction is dependent upon the area of contact The magnitude of the limiting friction bears a constant ratio to the normal reaction between two surfaces The force of friction depends upon the roughness of the surface ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics For the given values of initial velocity of projection and angle of inclination of the plane, the maximum range for a projectile projected upwards will be obtained, if the angle of projection is α = π/4 - β/2 α = π/4 - β/2 α = β/2 - π/2 α = π/2 + β/2 α = π/4 - β/2 α = π/4 - β/2 α = β/2 - π/2 α = π/2 + β/2 ANSWER DOWNLOAD EXAMIANS APP
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