Applied Mechanics and Graphic Statics The resultant of two forces acting at right angles is √34 kg and acting at 60° is 70 kg. The forces are 2 kg and 3 kg 1 kg and 4 kg √3 kg and √5 kg 3 kg and 5 kg 2 kg and 3 kg 1 kg and 4 kg √3 kg and √5 kg 3 kg and 5 kg ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A disc of mass 4 kg, radius 0.5 m and moment of inertia 3 kg.m² rolls on a horizontal surface so that its center moves with speed 5 m/see. Kinetic energy of the disc is 150 J 50 J 200 J 400 J 150 J 50 J 200 J 400 J ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The member forces in a statically in determinate truss Cannot be obtained by graphic statics Can be obtained by graphic statics by trial and error May be obtained by graphic statics Can be obtained by graphic statics Cannot be obtained by graphic statics Can be obtained by graphic statics by trial and error May be obtained by graphic statics Can be obtained by graphic statics ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A stone of mass 1 kg is tied to a string of length 1 m and whirled in a horizontal circle at a constant angular speed 5 rad/sec. The tension in the string is, 10 N 25 N 5 N 15 N 10 N 25 N 5 N 15 N ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics ‘u₁’ and ‘u₂’ are the velocities of approach of two moving bodies in the same direction and their corresponding velocities of separation are ‘v₁’ and ‘v₂’. As per Newton's law of collision of elastic bodies, the coefficient of restitution (e) is given by e = u₂ - u₁/v₁ - v₂ e = v₁ - v₂/u₂ - u₁ e = v₂ - v₁/u₁ - u₂ e = v₁ - v₂/u₂ + u₁ e = u₂ - u₁/v₁ - v₂ e = v₁ - v₂/u₂ - u₁ e = v₂ - v₁/u₁ - u₂ e = v₁ - v₂/u₂ + u₁ ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A particle moves along a straight line such that distance ‘x’ traversed in ‘t’ seconds is given by x = t²(t + 1), the acceleration of the particle, will be 3t³ - 2t 3t² + 2t 6t - 2 6t + 2 3t³ - 2t 3t² + 2t 6t - 2 6t + 2 ANSWER DOWNLOAD EXAMIANS APP