Concrete Technology and Design of Concrete Structures The relation between modulus of rupture fcr, splitting strength fcs and direct tensile strength fcl is given by fc5>fcr>fC fcr tcr – rcs = tct fcr>fcs>fc. fc5>fcr>fC fcr tcr – rcs = tct fcr>fcs>fc. ANSWER DOWNLOAD EXAMIANS APP
Concrete Technology and Design of Concrete Structures Strength of concrete increases with decrease in size of aggregate decrease in curing time increase in fineness of cement increase in water-cement ratio decrease in size of aggregate decrease in curing time increase in fineness of cement increase in water-cement ratio ANSWER DOWNLOAD EXAMIANS APP
Concrete Technology and Design of Concrete Structures In the design of a front counterfort in a counterfort retaining wall, the main reinforcement is provided oni) bottom face near counterfortii) top face near counterfortiii) bottom face near centre of spaniv) top face near centre of spanThe correct answer is only (i) only (ii) both (ii) and (iii) both (i) and (iv) only (i) only (ii) both (ii) and (iii) both (i) and (iv) ANSWER DOWNLOAD EXAMIANS APP
Concrete Technology and Design of Concrete Structures For a reinforced concrete section, the shape of shear stress diagram is wholly parabolic parabolic above neutral axis and rectangular below neutral axis wholly rectangular rectangular above neutral axis and parabolic below neutral axis wholly parabolic parabolic above neutral axis and rectangular below neutral axis wholly rectangular rectangular above neutral axis and parabolic below neutral axis ANSWER DOWNLOAD EXAMIANS APP
Concrete Technology and Design of Concrete Structures The compressive strength of 100 mm cube as compared to 150 mm cube is always None of these less equal more None of these less equal more ANSWER DOWNLOAD EXAMIANS APP
Concrete Technology and Design of Concrete Structures In a ring beam subjected to uniformly distributed load i) shear force at mid span is zero ii) shear force at mid span is maximum iii) torsion at mid span is zero iv) torsion at mid span is maximum The correct answer is (i) and (iii) (ii) and (iii) (i) and (iv) (ii) and (iv) (i) and (iii) (ii) and (iii) (i) and (iv) (ii) and (iv) ANSWER DOWNLOAD EXAMIANS APP
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