Concrete Technology and Design of Concrete Structures The relation between modulus of rupture fcr, splitting strength fcs and direct tensile strength fcl is given by fc5>fcr>fC tcr – rcs = tct fcr fcr>fcs>fc. fc5>fcr>fC tcr – rcs = tct fcr fcr>fcs>fc. ANSWER DOWNLOAD EXAMIANS APP
Concrete Technology and Design of Concrete Structures When shear stress exceeds the permissible limit in a slab, then it is reduced by Providing shear reinforcement Using high strength steel Using thinner bars but more in number Increasing the depth Providing shear reinforcement Using high strength steel Using thinner bars but more in number Increasing the depth ANSWER DOWNLOAD EXAMIANS APP
Concrete Technology and Design of Concrete Structures The fineness modulus of fine aggregate is in the range of 6.0 to 8.5 2.0 to 3.5 5.0 to 7.0 3.5 to 5.0 6.0 to 8.5 2.0 to 3.5 5.0 to 7.0 3.5 to 5.0 ANSWER DOWNLOAD EXAMIANS APP
Concrete Technology and Design of Concrete Structures In T-shaped R C. retaining walls, the main reinforcement in the stem is provided on the inner face in both directions the front face in both directions the front face in one direction the inner face in one direction the inner face in both directions the front face in both directions the front face in one direction the inner face in one direction ANSWER DOWNLOAD EXAMIANS APP
Concrete Technology and Design of Concrete Structures In a ring beam subjected to uniformly distributed loadi) shear force at mid span is zeroii) shear force at mid span is maximumiii) torsion at mid span is zeroiv) torsion at mid span is maximum The correct answer is (ii) and (iii) (i) and (iii) (i) and (iv) (ii) and (iv) (ii) and (iii) (i) and (iii) (i) and (iv) (ii) and (iv) ANSWER DOWNLOAD EXAMIANS APP
Concrete Technology and Design of Concrete Structures Sinking of an intermediate support of a continuous beami) reduces the negative moment at supportii) increases the negative moment at supportiii) reduces the positive moment at center of spaniv) increases the positive moment at center of span The correct answer is (i) and (iv) (ii) and (iv) (i) and (iii) (ii) and (iii) (i) and (iv) (ii) and (iv) (i) and (iii) (ii) and (iii) ANSWER DOWNLOAD EXAMIANS APP
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