Concrete Technology and Design of Concrete Structures The relation between modulus of rupture fcr, splitting strength fcs and direct tensile strength fcl is given by fcr>fcs>fc. tcr – rcs = tct fcr fc5>fcr>fC fcr>fcs>fc. tcr – rcs = tct fcr fc5>fcr>fC ANSWER DOWNLOAD EXAMIANS APP
Concrete Technology and Design of Concrete Structures Shrinkage of concrete depends upon i) humidity of atmosphere ii) passage of time iii) stress The correct answer is only (iii) (i) and (ii) (ii) and (iii) All (i), (ii) and (iii) only (iii) (i) and (ii) (ii) and (iii) All (i), (ii) and (iii) ANSWER DOWNLOAD EXAMIANS APP
Concrete Technology and Design of Concrete Structures If the depth of neutral axis for a singly reinforced rectangular section is represented by kd in working stress design, then the value of k for balanced section depends on as, only depends on aCbC only depends on both crst and acbc is independant of both ast and acbc where d is the effective depth, ast is per-missible stress in steel in tension and ocbc is permissible stress in concrete in bending compression. depends on as, only depends on aCbC only depends on both crst and acbc is independant of both ast and acbc where d is the effective depth, ast is per-missible stress in steel in tension and ocbc is permissible stress in concrete in bending compression. ANSWER DOWNLOAD EXAMIANS APP
Concrete Technology and Design of Concrete Structures The compressive strength of 100 mm cube as compared to 150 mm cube is always less None of these equal more less None of these equal more ANSWER DOWNLOAD EXAMIANS APP
Concrete Technology and Design of Concrete Structures If nominal shear stress tv exceeds the design shear strength of concrete xc, the nominal shear reinforcement as per IS : 456-1978 shall be provided for carrying a shear stress equal to xv xc Tv + Tc xv xc Tv + Tc ANSWER DOWNLOAD EXAMIANS APP
Concrete Technology and Design of Concrete Structures Sinking of an intermediate support of a continuous beam i) reduces the negative moment at support ii) increases the negative moment at support iii) reduces the positive moment at center of span iv) increases the positive moment at center of span The correct answer is (i) and (iv) (i) and (iii) (ii) and (iv) (ii) and (iii) (i) and (iv) (i) and (iii) (ii) and (iv) (ii) and (iii) ANSWER DOWNLOAD EXAMIANS APP
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