Concrete Technology and Design of Concrete Structures The relation between modulus of rupture fcr, splitting strength fcs and direct tensile strength fcl is given by fc5>fcr>fC fcr fcr>fcs>fc. tcr – rcs = tct fc5>fcr>fC fcr fcr>fcs>fc. tcr – rcs = tct ANSWER DOWNLOAD EXAMIANS APP
Concrete Technology and Design of Concrete Structures Diagonal tension in a beam Remains same Increases below the neutral axis and decreases above the neutral axis Is maximum at neutral axis Decreases below the neutral axis and increases above the neutral axis Remains same Increases below the neutral axis and decreases above the neutral axis Is maximum at neutral axis Decreases below the neutral axis and increases above the neutral axis ANSWER DOWNLOAD EXAMIANS APP
Concrete Technology and Design of Concrete Structures In symmetrically reinforced sections, shrinkage stresses in concrete and steel are respectively compressive and tensile both tensile tensile and compressive both compressive compressive and tensile both tensile tensile and compressive both compressive ANSWER DOWNLOAD EXAMIANS APP
Concrete Technology and Design of Concrete Structures In the design of a front counterfort in a counterfort retaining wall, the main reinforcement is provided on i) bottom face near counterfort ii) top face near counterfort iii) bottom face near centre of span iv) top face near centre of span The correct answer is only (i) only (ii) both (ii) and (iii) both (i) and (iv) only (i) only (ii) both (ii) and (iii) both (i) and (iv) ANSWER DOWNLOAD EXAMIANS APP
Concrete Technology and Design of Concrete Structures Modulus of elasticity of steel as per IS : 456-1978 shall be taken as 200 kN/cm² 200kN/mm² 20 kN/cm² 2xl06N/cm² 200 kN/cm² 200kN/mm² 20 kN/cm² 2xl06N/cm² ANSWER DOWNLOAD EXAMIANS APP
Concrete Technology and Design of Concrete Structures In a ring beam subjected to uniformly distributed loadi) shear force at mid span is zeroii) shear force at mid span is maximumiii) torsion at mid span is zeroiv) torsion at mid span is maximumThe correct answer is (i) and (iv) (i) and (iii) (ii) and (iv) (ii) and (iii) (i) and (iv) (i) and (iii) (ii) and (iv) (ii) and (iii) ANSWER DOWNLOAD EXAMIANS APP
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