Fractions and Decimals The rational number for recurring decimal 0.125125.... is: 125/99 125/100 125/1000 125/999 125/99 125/100 125/1000 125/999 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP _0.125125... = 0.125 =125/999
Fractions and Decimals The value of 47 / 10000 is ? 0.00047 0.0047 0.047 0.47 0.00047 0.0047 0.047 0.47 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 47/10000 = .0047
Fractions and Decimals 0.000033 / 0.11=? 0.03 0.003 0.0003 0.3 0.03 0.003 0.0003 0.3 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 0.000033 / 0.11= 0.0033 / 11=.0003
Fractions and Decimals What should be subtracted from the multiplication of 0.527 and 2.013 to get 1 ? 60.851 None of these 6085.1 0.060851 60.851 None of these 6085.1 0.060851 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP ∵ 0.527 x 2.013 = 1.060851Hence, the required number = 1.060851 - 1 = 0.060851.
Fractions and Decimals (.356 x .365 - 2 x .365 x .106 + .106 x .106) / (.632 x .632 + 2 x .632 x .368 +.368 x .368) = ? .0625 .625 62.5 6.25 .0625 .625 62.5 6.25 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given expression = [(.356)² -2 x .356 x .106 + (.106)²] / [(.632)²+2 x .632 x .368 +(.368)²]= (a² -2ab + b²) / (c²+2cd+d²)= (a - b)² / (c + d)²= (.356 -.106)² / (.632 + .368)²= (.25)² = .0625
Fractions and Decimals ( .803 x .647 + .803 x .353 ) = ? .803 803 80.3 8.03 .803 803 80.3 8.03 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given Expression = ( .803 x .647 + .803 x .353 )= 803 x (.647 + .353)= .803 x 1 = .803
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