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Alligation or Mixture problems

Alligation or Mixture problems
The ratio of milk and water in 66 kg of adulterated milk is 5 : 1. Water is added to it to make the ratio 5 : 3. The quantity of water added is ?

20 kg
16·500 kg
24·750 kg
22 kg

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Alligation or Mixture problems
80 litre mixture of milk and water contains 10% milk. How much milk (in litres) must be added to make water percentage in the mixture as 80%?

12
9
10
8

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let initial quantity be Q, and final quantity be F F = Q(1 - 8/Q) 4 => Q = 20

Alligation or Mixture problems
A container contains 40 litres of milk.From this container 4 litres of milk was taken out and replaced by water. This process was repeated further two times. How much milk is now contained by the container.

27.36 litres
26.34 litres
29.16 litres
28 litres

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Amount of milk left after 3 operations   40 1 - 4 40 3 = 40 * 9 10 * 9 10 * 9 10 = 29 . 16  litres

Alligation or Mixture problems
In a triangle XYZ , which of the following conditions is true

XY YZ < XZ
XY + ZX < YZ
XY + YZ < ZX
XY YZ > ZX

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Ratio of milk and water = 2 : 1 Quantity of milk = 60 X 2/3 = 40 litre Quantity of water = 20 litre To make ratio, 1: 2, we have to double the water that of milk So, water should be 80 litre. That means 80 ? 20 = 60 litre water to be added.

Alligation or Mixture problems
One type of liquid contains 25 % of benzene, the other contains 30% of benzene. A can is filled with 6 parts of the first liquid and 4 parts of the second liquid. Find the percentage of benzene in the new mixture.

27 %
26 %
21 %
29 %

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let the percentage of benzene = X(30 - X)/(X- 25) = 6/4 = 3/2 => 5X = 135  X = 27 So, required percentage of benzene = 27 %

Alligation or Mixture problems
How much water (in litres) must be added to 80 litres solution of milk and water containing 10% milk, so that it becomes a 5% milk solution?

80
20
40
10

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let initial quantity be Q, and final quantity be F F = Q(1 - 8/Q) 4 => Q = 20

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