Alligation or Mixture problems In a courtyard there are many chickens and goats. If heads are counted, it comes to 100 but when legs are counted, it comes to 320. Find the number of chickens and goats in the courtyard. 20 , 50 50 , 50 40 , 60 30 , 70 20 , 50 50 , 50 40 , 60 30 , 70 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Average no. of legs per head = (320 / 100) = (16 / 5) or, 3 : 2 No. of goats = (3 / 3 + 2) × 100 = 60 No. of chickens = 100 ? 60 = 40.
Alligation or Mixture problems A mixture of 20 kg of spirit and water contains 10 % water. How much water must be added to this mixture to raise the percentage of water to 25 %? 5 kg 30 kg 8 kg 4 kg 5 kg 30 kg 8 kg 4 kg ANSWER DOWNLOAD EXAMIANS APP
Alligation or Mixture problems A mixture contains 25% milk and rest water. What percent of this mixture must taken out and replaced with milk so that in mixture milk and water may become equal. 31% 33.33% 31.8% 29.85% 31% 33.33% 31.8% 29.85% ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Now, take percentage of milk and applying mixture rule 25 100 50 50 25 = 2 : 1 Hence required answer = 1/3 or 33.33%
Alligation or Mixture problems A can contains a mixture of 2 liquids A and B in proportion 7 : 5 when 9 liters of mixture are drawn off and the can is filled with B, the proportion of A and B becomes 7 : 9. How many liters of liquid A was contained by the can initially? 10 20 25 21 10 20 25 21 ANSWER DOWNLOAD EXAMIANS APP
Alligation or Mixture problems An alloy is made by mixing metal A costing Rs 2000/kg and metal B costing Rs 400/kg in the ratio A:B = 3:1. What is the cost (in Rs) of 8 kilograms of this alloy? 6400 1600 9800 12800 6400 1600 9800 12800 ANSWER DOWNLOAD EXAMIANS APP
Alligation or Mixture problems 8 litres are drawn from a flask containing milk and then filledwith water. The operation is performed 3 more times. Theratio of the quantity of milk left and total solution is 81/625.How much milk the flask initially holds? 30 ltr 40 ltr 10 ltr 20 ltr 30 ltr 40 ltr 10 ltr 20 ltr ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let initial quantity be Q, and final quantity be F F = Q(1 - 8/Q) 4 => Q = 20
EXAMIANS