Applied Mechanics and Graphic Statics The numbers of funicular polygons which can be drawn to pass through two specified points in the space diagram are 2 1 Infinity Zero 2 1 Infinity Zero ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The torque produced by a force depends on(i) The magnitude of the force(ii) The direction of the force(iii) The point of application of the force relative to origin Both (i) and (ii) Both (i) and (iii) All (i), (ii) and (iii) Only (i) Both (i) and (ii) Both (i) and (iii) All (i), (ii) and (iii) Only (i) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics When a circular wheel rolls on a straight track, then the shape of body centrode and space centrode respectively are Circle and parabola Straight line and parabola Straight line and circle Circle and straight line Circle and parabola Straight line and parabola Straight line and circle Circle and straight line ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The phenomenon of collision of two elastic bodies takes place because bodies Immediately after collision come momentarily to rest Attempt to regain its original shape due to their elasticities Tend to compress each other till they are compressed maximum possible All listed here Immediately after collision come momentarily to rest Attempt to regain its original shape due to their elasticities Tend to compress each other till they are compressed maximum possible All listed here ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A block of weight 50 kg is placed on a horizontal plane. When a horizontal force of 18 kg is applied, the block is just on the point of motion. The angle of friction is 17° 48' 18° 48' 20° 48' 19° 48' 17° 48' 18° 48' 20° 48' 19° 48' ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics ‘u₁’ and ‘u₂’ are the velocities of approach of two moving bodies in the same direction and their corresponding velocities of separation are ‘v₁’ and ‘v₂’. As per Newton's law of collision of elastic bodies, the coefficient of restitution (e) is given by e = v₂ - v₁/u₁ - u₂ e = v₁ - v₂/u₂ + u₁ e = u₂ - u₁/v₁ - v₂ e = v₁ - v₂/u₂ - u₁ e = v₂ - v₁/u₁ - u₂ e = v₁ - v₂/u₂ + u₁ e = u₂ - u₁/v₁ - v₂ e = v₁ - v₂/u₂ - u₁ ANSWER DOWNLOAD EXAMIANS APP
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