Applied Mechanics and Graphic Statics The numbers of funicular polygons which can be drawn to pass through two specified points in the space diagram are 1 2 Zero Infinity 1 2 Zero Infinity ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics ‘ω’ rad/sec is the angular velocity of a crank whose radius is ‘r’. If it makes θ° with inner dead centre and obliquity of the connecting rod ‘l’ is ‘ϕ’, the velocity v of the piston, is given by the equation ω (l sin ϕ + r cos ϕ tan θ) ω² (l cos ϕ + r sin ϕ tan θ) ω² (l sin ϕ - r cos θ tan ϕ) ω² (l sin ϕ + r cos φ tan θ) ω (l sin ϕ + r cos ϕ tan θ) ω² (l cos ϕ + r sin ϕ tan θ) ω² (l sin ϕ - r cos θ tan ϕ) ω² (l sin ϕ + r cos φ tan θ) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A shell travelling with a horizontal velocity of 100 m/sec explodes and splits into two parts, one of mass 10 kg and the other of 15 kg. The 15 kg mass drops vertically downward with initial velocity of 100 m/sec and the 10 kg mass begins to travel at an angle to the horizontal of tan”1 x, where x is 43895 43894 43954 43926 43895 43894 43954 43926 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The resultant of two forces P and Q is R. If Q is doubled, the new resultant is perpendicular to P. Then, P = Q P = R Q = R None of these P = Q P = R Q = R None of these ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If a particle moves with a uniform angular velocity ‘ω’ radians/sec along the circumference of a circle of radius ‘r’, the equation for the velocity of the particle, is v = ω √(r² - y²) v = ω √(r² + y²) v = ω √(y² - r²) y = ω √(y - r) v = ω √(r² - y²) v = ω √(r² + y²) v = ω √(y² - r²) y = ω √(y - r) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The mechanical advantage of an ideal machine is 100. For moving the local through 2 m, the effort moves through 2.5 m 0.02 m 20 m 2 m 2.5 m 0.02 m 20 m 2 m ANSWER DOWNLOAD EXAMIANS APP
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