Fractions and Decimals The number 0.127 is how much greater than 1/8 ? 1/1000 1/500 1/800 1/300 1/1000 1/500 1/800 1/300 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 0.127 expressed as a fraction = 127/10001/8 can also be expressed as (1 x 125) / (8 x 125) = 125/1000The difference is 2/1000, which is 1/500
Fractions and Decimals The price of commodity X increases by 40 paise every year, while the price of commodity Y increases by 15 paise every year. If in 2001, the price of commodity X was Rs. 4.20 and that of Y was Rs. 6.3 2011 2013 2014 2012 2011 2013 2014 2012 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Suppose commodity X wil cost 40 paise more than Y after Z years.Then, (4.20 + 0.40Z) - (6.30 + 0.15Z) = 0.40 0.25Z = 0.40 + 2.10 Z= X will cost 40 paise more than Y 10 years after 2001 . i.e in 2011
Fractions and Decimals If 3 is added to the denominator of a fraction, it becomes 1/3 and if 4 be added to its numerator, It becomes 3/4, then fraction is ? None of these 5/12 1/16 3/20 None of these 5/12 1/16 3/20 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the required fraction be p/q∵ p / (q + 3) = 1/3⇒ 3p - q = 3 ...(i)and, (p + 4) / q = 3/4 ⇒ 4p - 3q = -16 ...(ii)Solving these equations, we get p = 5, q = 12∴ Required fraction = 5/12
Fractions and Decimals (0.47 x 0.47 x 0.47 - 0.33 x 0.33 x 0.33) / (0.47 x 0.47 + 0.47 x 0.33 + 0.33 x 0.33) = ? 14 0.14 0.014 1.4 14 0.14 0.014 1.4 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given expression = [(0.47)³ - (0.33)³] / [(0.47)² + 0.47 x 0.33 + (0.33)²]= [a³ - b³ ] / [ a² + ab + b²] = [(a-b) (a² + ab + b²)] / [(a² + ab + b²)]= (a - b) = (0.47 - 0.33) = 0.14
Fractions and Decimals (1.1 + 1.1 + 1.1 + 1.1) x 1.1 x 1.1 = ? = ? x 0.121 44 54 33 64 44 54 33 64 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP ? = (1.1 + 1.1 + 1.1 + 1.1) x 1.1 x 1.1/0.121 = (4.4 x 1.1 x 1.1)/0.121 = 44
Fractions and Decimals The expression (11.98 * 11.98 + 11.98 * (x) + 0.02 * 0.02) will be a perfect square for x equal to : 0.04 None of these 0.4 4 0.04 None of these 0.4 4 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given = (11.98)^2 + (0.02)^2 + 11.98 * x. For the given expression to be a perfect square, we must have11.98 * x = 2 * 11.98 * 0.02=> x = 0.04
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