Applied Mechanics and Graphic Statics The necessary condition of equilibrium of a body is: All (A), (B) and (C) Algebraic sum of horizontal components of all the forces must be zero Algebraic sum of vertical components of all the forces must be zero Algebraic sum of the moments of the forces about a point must be zero All (A), (B) and (C) Algebraic sum of horizontal components of all the forces must be zero Algebraic sum of vertical components of all the forces must be zero Algebraic sum of the moments of the forces about a point must be zero ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The centre of gravity of the trapezium as shown in below figure from the side is at a distance of (h/3) × [(2b + a)/(b + a)] (h/2) × [(b + 2a)/(b + a)] (h/3) × [(b + 2a)/(b + a)] (h/2) × [(2b + a)/(b + a)] (h/3) × [(2b + a)/(b + a)] (h/2) × [(b + 2a)/(b + a)] (h/3) × [(b + 2a)/(b + a)] (h/2) × [(2b + a)/(b + a)] ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If a body is lying on a plane whose inclination with the horizontal is less than the angle of friction, then i. a force is required to move the body upwards ii. a force is required to move the body downward iii. the body will not be in equilibrium The correct answer is both (i) and (ii) only (i) both (i) and (iii) only (ii) both (i) and (ii) only (i) both (i) and (iii) only (ii) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A glass ball is shot to hit a wall from a point on a smooth floor. If the ball returns back to the point of projection in twice the time taken in reaching the wall, the coefficient of restitution between the glass ball and the wall is 0.5 0.25 0.33 0.4 0.5 0.25 0.33 0.4 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The unit of moments in M.K.S system, is kg.m kg/m2 kg/sec2 kg/sec kg.m kg/m2 kg/sec2 kg/sec ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The velocity of a body fallen from height ‘h’, on reaching the ground is given by v = 1/√(2gh) v = 2gh² v = √(2gh) v = 2gh v = 1/√(2gh) v = 2gh² v = √(2gh) v = 2gh ANSWER DOWNLOAD EXAMIANS APP
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