Engineering Mechanics The moment of inertia of a thin spherical shell of mass m and radius r, about its diameter is 2mr²/5 mr²/3 2mr²/3 3mr²/5 2mr²/5 mr²/3 2mr²/3 3mr²/5 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics A semicircular disc rests on a horizontal surface with its top flat surface horizontal and circular portion touching down. The coefficient of friction between semi circular disc and horizontal surface is µ. This disc is to be pulled by a horizontal force applied at one edge and it always remains horizontal. When the disc is about to start moving, its top horizontal force will Remain horizontal Slant down towards direction of pull None of these Slant up towards direction of pull Remain horizontal Slant down towards direction of pull None of these Slant up towards direction of pull ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Mass moment of inertia of a thin rod about its one end is ___________ the mass moment of inertia of the same rod about its mid-point Twice Four times Thrice Same as Twice Four times Thrice Same as ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The force applied on a body of mass 100 kg to produce an acceleration of 5 m/s2, is 500 N 100 N 20 N None of these 500 N 100 N 20 N None of these ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics One joule means that Work is done by a force of 1 N when it displaces a body through 1 m Work is done by a force of 1 dyne when it displaces a body through 1 cm Work is done by a force of 1 g when it displaces a body through 1 cm Work is done by a force of 1 kg when it displaces a body through 1 m Work is done by a force of 1 N when it displaces a body through 1 m Work is done by a force of 1 dyne when it displaces a body through 1 cm Work is done by a force of 1 g when it displaces a body through 1 cm Work is done by a force of 1 kg when it displaces a body through 1 m ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The loss of kinetic energy during inelastic impact, is given by (where m1 = Mass of the first body,m2 = Mass of the second body, and u1 and u2 = Velocities of the first and second bodies respectively.) [2(m₁ + m₂)/m₁ m₂] (u₁² - u₂²) [m₁ m₂/2(m₁ + m₂)] (u₁ - u₂)² [m₁ m₂/2(m₁ + m₂)] (u₁² - u₂²) [2(m₁ + m₂)/m₁ m₂] (u₁ - u₂)² [2(m₁ + m₂)/m₁ m₂] (u₁² - u₂²) [m₁ m₂/2(m₁ + m₂)] (u₁ - u₂)² [m₁ m₂/2(m₁ + m₂)] (u₁² - u₂²) [2(m₁ + m₂)/m₁ m₂] (u₁ - u₂)² ANSWER DOWNLOAD EXAMIANS APP
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