Concrete Technology and Design of Concrete Structures The minimum cover to the ties or spirals should not be less than 25 mm 15 mm 50mm 20 mm 25 mm 15 mm 50mm 20 mm ANSWER DOWNLOAD EXAMIANS APP
Concrete Technology and Design of Concrete Structures A beam curved in plan is designed for shear and torsion bending moment and torsion bending moment and shear bending moment, shear and torsion shear and torsion bending moment and torsion bending moment and shear bending moment, shear and torsion ANSWER DOWNLOAD EXAMIANS APP
Concrete Technology and Design of Concrete Structures In a ring beam subjected to uniformly distributed load i) shear force at mid span is zero ii) shear force at mid span is maximum iii) torsion at mid span is zero iv) torsion at mid span is maximum The correct answer is (i) and (iii) (i) and (iv) (ii) and (iii) (ii) and (iv) (i) and (iii) (i) and (iv) (ii) and (iii) (ii) and (iv) ANSWER DOWNLOAD EXAMIANS APP
Concrete Technology and Design of Concrete Structures Critical section for shear in case of flat slabs is at a distance of d/2 from periphery of column/capital/ drop panel at the periphery of column at the drop panel of slab effective depth of slab from periphery of column/drop panel d/2 from periphery of column/capital/ drop panel at the periphery of column at the drop panel of slab effective depth of slab from periphery of column/drop panel ANSWER DOWNLOAD EXAMIANS APP
Concrete Technology and Design of Concrete Structures If nominal shear stress tv exceeds the design shear strength of concrete xc, the nominal shear reinforcement as per IS : 456-1978 shall be provided for carrying a shear stress equal to xv xc Tv + Tc xv xc Tv + Tc ANSWER DOWNLOAD EXAMIANS APP
Concrete Technology and Design of Concrete Structures The relation between modulus of rupture fcr, splitting strength fcs and direct tensile strength fcl is given by fcr fc5>fcr>fC fcr>fcs>fc. tcr – rcs = tct fcr fc5>fcr>fC fcr>fcs>fc. tcr – rcs = tct ANSWER DOWNLOAD EXAMIANS APP
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