Power Systems The load current in short circuit calculations are neglected because short circuit currents are greatly out of phase with load currents nether 1 nor 2 both 1 and 2 short circuit currents are much larger than load currents short circuit currents are greatly out of phase with load currents nether 1 nor 2 both 1 and 2 short circuit currents are much larger than load currents ANSWER DOWNLOAD EXAMIANS APP
Power Systems In thermal plant most of the energy is wasted in ESP turbines condenser boiler ESP turbines condenser boiler ANSWER DOWNLOAD EXAMIANS APP
Power Systems An unloaded generator with a pre-fault voltage 1 pu has the following sequence impedance: Z0 = j 0.15 pu, Z1 = Z2 = j 0.25 pu The neutral is grounded with a reactance of 0.05 pu. The fault current in pu for single line to ground fault is 4.28 pu 2.5 pu 3.75 pu 7.25 pu 4.28 pu 2.5 pu 3.75 pu 7.25 pu ANSWER DOWNLOAD EXAMIANS APP
Power Systems The rating of fuse wire is always expressed in kWh. amperes. ampere-hours. ampere-volts. kWh. amperes. ampere-hours. ampere-volts. ANSWER DOWNLOAD EXAMIANS APP
Power Systems A transmission line has impedance of (0.005 + j0.05) pu. Find the line at which maximum value of negative DC off set current is produced, if it is applied with Vm sinωt? 9.68 msec 1.47 msec 2.63 msec 4.68 msec 9.68 msec 1.47 msec 2.63 msec 4.68 msec ANSWER DOWNLOAD EXAMIANS APP
Power Systems The positive, negative and zero sequence impedances of a transmission line are 0.5,0.5 and 1.1 pu respectively. The self (Zs) and mutual (Zm) impedances of the line will be given by Zs = 0.2 pu, Zm =0.7 pu Zs = 0.6 pu, Zm =0.5 pu Zs = 0.7 pu, Zm =0.2 pu Zs = 0.5 pu, Zm =0.6 pu Zs = 0.2 pu, Zm =0.7 pu Zs = 0.6 pu, Zm =0.5 pu Zs = 0.7 pu, Zm =0.2 pu Zs = 0.5 pu, Zm =0.6 pu ANSWER DOWNLOAD EXAMIANS APP