Surveying The line of collimation method of reduction of levels, does not provide a check on Fore sights Reduced levels Intermediate sights Back sights Fore sights Reduced levels Intermediate sights Back sights ANSWER DOWNLOAD EXAMIANS APP
Surveying The two point problem and three point problem are methods of resection resection and orientation orientation traversing resection resection and orientation orientation traversing ANSWER DOWNLOAD EXAMIANS APP
Surveying A plate parallel is the line on the plane of the negative Along the bisector of the angle between the principal line and a perpendicular line through principal plane Parallel to the principal line None of these Perpendicular to the principal line Along the bisector of the angle between the principal line and a perpendicular line through principal plane Parallel to the principal line None of these Perpendicular to the principal line ANSWER DOWNLOAD EXAMIANS APP
Surveying The correction applied to the measured base of length ‘L’ is Tension = (P - Ps)L/AE All of these Slope = (h²/2L) + (h⁴/8L³) where h is height difference of end supports Sag = L³w²/24P² where w is the weight of tape/m Tension = (P - Ps)L/AE All of these Slope = (h²/2L) + (h⁴/8L³) where h is height difference of end supports Sag = L³w²/24P² where w is the weight of tape/m ANSWER DOWNLOAD EXAMIANS APP
Surveying For a tacheometer the additive and multi-plying constants are respectively 0 and 100 100 and 100 100 and 0 0 and 0 0 and 100 100 and 100 100 and 0 0 and 0 ANSWER DOWNLOAD EXAMIANS APP
Surveying The net ground area of a vertical photograph 20 cm × 20 cm on scale 1 : 10,000 having overlaps 60% and 30%, is 0.50 sq km 0.56 sq km 0.64 sq km 0.60 sq km 0.50 sq km 0.56 sq km 0.64 sq km 0.60 sq km ANSWER DOWNLOAD EXAMIANS APP
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