Area Problems The length of a rectangle is double while its breadth is halved. What is the percentage change in area? No change 50 None of these 75 No change 50 None of these 75 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let length = l and breadth = bThen, area = lb New length = 2lAnd new breadth = b/2 ? New area = ( 2l ) x (b/2) = lbSo, there is no change in area .
Area Problems If a regular hexagon is inscribed in a circle of radius, r then its perimeter? 6r 9r 12r 3r 6r 9r 12r 3r ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Length of each side of hexagoan = radius of circle ? its perimeter = 6r
Area Problems Find the area of a rectangle having 15m length and 8m breadth. 120 sq m 111 sq m 115 sq m 125 sq m 120 sq m 111 sq m 115 sq m 125 sq m ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required area = Length x Breadth= 15 x 8 = 120 sq m
Area Problems A rectangular carpet has an area of 120 sq. m and a perimeter of 46 m . The length of its diagonal is? 17 m 20 m 15 m 16 m 17 m 20 m 15 m 16 m ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let length = a metres and breadth = b metres Then, 2(a+b)= 46 ? (a+b) =23 and ab =120 ? Diagonal = ?a2 + b2?(23)2-2 x 120?289 = 17 m
Area Problems The radius of a circle is so increased that its circumference increased by 5%. The area of the circle, then increases by 10.25% 11.25% 12.5% 10.5 % 10.25% 11.25% 12.5% 10.5 % ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Increase in circumference of circle = 5%? Increase in radius is also 5%.Now, increase in area of circle = 2a + (a2/100) %Where, a = increase in radius= 2 x 5 + (5 x 5)/100 % = 10.25%
Area Problems The two parallel sides of a trapezium are 1 meters and 2 meters respectively . The perpendicular distance between them is 6 meters. The area of the trapezium is? 6 sq. meters . 18 sq. meters . 9 sq. meters . 12 sq. meters . 6 sq. meters . 18 sq. meters . 9 sq. meters . 12 sq. meters . ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area of trapezium = 1/2 x sum of parallel sides x perpendicular distance between them= 1/2 (1 + 2) x 6 m2= 9 m2
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