Area Problems The length of a rectangle is double while its breadth is halved. What is the percentage change in area? 75 50 None of these No change 75 50 None of these No change ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let length = l and breadth = bThen, area = lb New length = 2lAnd new breadth = b/2 ? New area = ( 2l ) x (b/2) = lbSo, there is no change in area .
Area Problems The length and breadth of a square are increased by 40% and 30% respectively. The area of a resulting rectangle exceeds the area of the square by? 82% 62% None of these 42% 82% 62% None of these 42% ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the side of the square = 100 m So area of square = 100 x 100 = 10000.New length = 140 m, New breadth = 130 mIncrease in area = [(140 x 130) - (100 x 100)] m2= 8200 m2? Required increase percent = (8200/ 10000) x 100 % = 82%
Area Problems The altitude of an equilateral triangle of side 2 ? 3 cm is? ? 3/4 1/2 cm 3 cm ? 3/2 cm ? 3/4 1/2 cm 3 cm ? 3/2 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP ? 1/2 x 2 ? x h = ?3/4 x (2 ?3)2? h = 3 cm.
Area Problems If the ratio of the area of two square is 9 : 1 the ratio of their perimeters is? 1:3 3:4 3:1 9:1 1:3 3:4 3:1 9:1 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the area of square be (9x)2 m2 and (x2) m2Then, their sides are (3x) m and x metres respectively? Ratio of their perimeters = 12x / 4x=3:1
Area Problems The ratio between the lenght and the breadth of a rectangle is 2 : 1. If breadth is 5 cm less than the length, what will be the parimeter of the rectangle? 35 cm 40 cm 25 cm 30 cm 35 cm 40 cm 25 cm 30 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let length = 2x and breadth = xAccording to the question, 2x - x = 5 ? x = 5? Required perimeter = 2(2x + x) = 6x= 30 cm
Area Problems A rectangular lawn 55m by 35m has two roads each 4m wide running in the middle of it. One parallel to the length and the other parallel to breadth. The cost of graveling the roads at 75 paise per sq meter is rs.258 rs.158 rs.58 rs.358 rs.258 rs.158 rs.58 rs.358 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP area of cross roads = (55 x 4) + (35 x 4)- (4 x 4) = 344sq m cost of graveling = 344 x (75/100) = Rs. 258
EXAMIANS