Chemical Engineering Thermodynamics The internal energy of a gas obeying P (V - b) RT (where, b is a positive constant and has a constant Cv), depends upon its Volume Temperature All of these Pressure Volume Temperature All of these Pressure ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics At 60° C, vapour pressure of methanol and water are 84.562 kPa and 19.953 kPa respectively. An aqueous solution of methanol at 60° C exerts a pressure of 39.223 kPa; the liquid phase and vapour phase mole fractions of methanol are 0.1686 and 0.5714 respectively. Activity co-efficient of methanol is 1.572 1.9398 3.389 4.238 1.572 1.9398 3.389 4.238 ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics For a given substance at a specified temperature, activity is __________ to fugacity. None of these Equal Inversely proportional Directly proportional None of these Equal Inversely proportional Directly proportional ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics An ideal liquid refrigerant should Both A and B Have low specific heat Not have a subatmospheric vapour pressure at the temperature in the refrigerator coils Not have unduly high vapour pressure at the condenser temperature Both A and B Have low specific heat Not have a subatmospheric vapour pressure at the temperature in the refrigerator coils Not have unduly high vapour pressure at the condenser temperature ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics Air enters an adiabatic compressor at 300K. The exit temperature for a compression ratio of 3, assuming air to be an ideal gas (Y = Cp/Cv = 7/5) and the process to be reversible, is 300(32/7) 300(33/5) 300(33/7) 300(35/7) 300(32/7) 300(33/5) 300(33/7) 300(35/7) ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics On a P-V diagram of an ideal gas, suppose a reversible adiabatic line intersects a reversible isothermal line at point A. Then at a point A, the slope of the reversible adiabatic line (∂P/∂V)S and the slope of the reversible isothermal line (∂P/∂V)T are related as (where, y = Cp/Cv) ) (∂P/∂V)S = (∂P/∂V)T (∂P/∂V)S = 1/y(∂P/∂V)T (∂P/∂V)S = [(∂P/∂V)T]Y (∂P/∂V)S = y(∂P/∂V)T (∂P/∂V)S = (∂P/∂V)T (∂P/∂V)S = 1/y(∂P/∂V)T (∂P/∂V)S = [(∂P/∂V)T]Y (∂P/∂V)S = y(∂P/∂V)T ANSWER DOWNLOAD EXAMIANS APP
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