Applied Mechanics and Graphic Statics The instantaneous centre of a member lies at the point of intersection of two lines drawn at the ends of the member such that the lines are inclined to the direction of motion of the ends at 60° 90° 45° 30° 60° 90° 45° 30° ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A trolley wire weighs 1 kg per metre length. The ends of the wire are attached to two poles 20 m apart. If the horizontal tension is 1000 kg, the central dip of the cable is 2 cm 3 cm 4 cm 5 cm 2 cm 3 cm 4 cm 5 cm ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A weight of 100 kg is supported by a string whose ends are attached to pegs ‘A’ and ‘B’ at the same level shown in below figure. The tension in the string is Applied Mechanics and Graphic Statics mcq question image 100 kg 120 kg 150 kg 130 kg 100 kg 120 kg 150 kg 130 kg ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If the tension in a cable supporting a lift moving upwards is twice the tension when the lift is moving downwards, the acceleration of the lift, is g/4 g/3 g/5 g/2 g/4 g/3 g/5 g/2 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics ‘u₁’ and ‘u₂’ are the velocities of approach of two moving bodies in the same direction and their corresponding velocities of separation are ‘v₁’ and ‘v₂’. As per Newton's law of collision of elastic bodies, the coefficient of restitution (e) is given by e = u₂ - u₁/v₁ - v₂ e = v₁ - v₂/u₂ - u₁ e = v₂ - v₁/u₁ - u₂ e = v₁ - v₂/u₂ + u₁ e = u₂ - u₁/v₁ - v₂ e = v₁ - v₂/u₂ - u₁ e = v₂ - v₁/u₁ - u₂ e = v₁ - v₂/u₂ + u₁ ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A uniform rod 9 m long weighing 40 kg is pivoted at a point 2 m from one end where a weight of 120 kg is suspended. The required force acting at the end in a direction perpendicular to rod to keep it equilibrium, at an inclination 60° with horizontal, is 100 kg 10 kg 60 kg 40 kg 100 kg 10 kg 60 kg 40 kg ANSWER DOWNLOAD EXAMIANS APP
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