Hydraulics and Fluid Mechanics in ME
A tank of uniform cross-sectional area (A) containing liquid upto height (H1) has an orifice of cross-sectional area (a) at its bottom. The time required to bring the liquid level from H1 to H2 will be

2A × (√H3/2 - √H3/2)/Cd × a × √(2g)
2A × √H₁/Cd × a × √(2g)
2A × (√H₁ - √H₂)/Cd × a × √(2g)
2A × √H₂/Cd × a × √(2g)

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Hydraulics and Fluid Mechanics in ME
A closed tank containing water is moving in a horizontal direction along a straight line at a constant speed. The tank also contains a steel ball and a bubble of air. If the tank is decelerated horizontally, theni) the ball will move to the frontii) the bubble will move to the frontiii) the ball will move to the reariv) the bubble will move to the rear Find out which of the above statements are correct ?

(iii) and (iv)
(i) and (ii)
(i) and (iv)
(ii) and (iii)

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Hydraulics and Fluid Mechanics in ME
The discharge through a large rectangular orifice is given by (where H1 = Height of the liquid above the top of the orifice, H2 = Height of the liquid above the bottom of the orifice, b = Breadth of the orifice, and Cd = Coefficient of discharge)

Q = (2/3) Cd × b × √(2g) × (H21/2 - H11/2)
Q = (2/3) Cd × b × √(2g) × (H2 - H1)
Q = (2/3) Cd × b × √(2g) × (H22 - H12)
Q = (2/3) Cd × b × √(2g) × (H23/2 - H13/2)

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Hydraulics and Fluid Mechanics in ME
Slip of a reciprocating pump is negative, when

Suction pipe is short and pump is running at low speeds
Suction pipe is long and delivery pipe is short and the pump is running at high speeds
Suction pipe is short and delivery pipe is long and the pump is running at low speeds
Delivery pipe is long and pump is running at high speeds

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Hydraulics and Fluid Mechanics in ME
Buoyant force is

The force necessary to maintain equilibrium of a submerged body
Equal to the volume of liquid displaced
The resultant force acting on a floating body
The resultant force on a body due to the fluid surrounding it

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