Engineering Thermodynamics The general law for the expansion or compression of gases, is pv = m R T pv = C pvn = C pvγ = C pv = m R T pv = C pvn = C pvγ = C ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics In an irreversible process, there is a No gain of heat Gain of heat No loss of heat Loss of heat No gain of heat Gain of heat No loss of heat Loss of heat ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics The following cycle is used for air craft refrigeration Carnot cycle Reversed Brayton cycle Joule cycle Brayton cycle Carnot cycle Reversed Brayton cycle Joule cycle Brayton cycle ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics Which of the following is the correct statement? All the reversible and irreversible engines have the same efficiency. All engines are designed as reversible in order to obtain maximum efficiency. Irreversible engines have maximum efficiency. All the reversible engines have the same efficiency. All the reversible and irreversible engines have the same efficiency. All engines are designed as reversible in order to obtain maximum efficiency. Irreversible engines have maximum efficiency. All the reversible engines have the same efficiency. ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics In order that a cycle be reversible, following must be satisfied When heat is being absorbed, temperature of hot source and working substance should be same When beat is being rejected, temperature of cold source and working substance should be same Free expansion or friction resisted expansion/compression process should not be encountered All of these When heat is being absorbed, temperature of hot source and working substance should be same When beat is being rejected, temperature of cold source and working substance should be same Free expansion or friction resisted expansion/compression process should not be encountered All of these ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics The air standard efficiency of an Otto cycle is given by (where r = Compression ratio, and γ = Ratio of specific heats) 1 - (1/ rγ - 1) 1 - rγ - 1 1 + (1/ rγ - 1) 1 + rγ - 1 1 - (1/ rγ - 1) 1 - rγ - 1 1 + (1/ rγ - 1) 1 + rγ - 1 ANSWER DOWNLOAD EXAMIANS APP
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