Applied Mechanics and Graphic Statics The force polygon representing a set of forces in equilibrium is a Open polygon Triangle Closed polygon Parallelogram Open polygon Triangle Closed polygon Parallelogram ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If a body is lying on a plane whose inclination with the horizontal is less than the angle of friction, theni. a force is required to move the body upwardsii. a force is required to move the body downwardiii. the body will not be in equilibriumThe correct answer is both (i) and (ii) both (i) and (iii) only (ii) only (i) both (i) and (ii) both (i) and (iii) only (ii) only (i) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics Two forces act an angle of 120°. If the greater force is 50 kg and their resultant is perpendicular to the smaller force, the smaller force is 30 kg 40 kg 50 kg 25 kg 30 kg 40 kg 50 kg 25 kg ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A stone was thrown vertically upwards from the ground with a velocity of 50 m/sec. After 5 seconds another stone was thrown vertically upwards from the same place. If both the stones strike the ground at the same time, then the velocity with which the second stone was thrown should be (Assume g = 10 m/sec²) 15 m/sec 25 m/sec 50 m/sec 40 m/sec 15 m/sec 25 m/sec 50 m/sec 40 m/sec ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A body is dropped from a height of 100 m and at the same time another body is projected vertically upward with a velocity of 10 m/sec. The two particles will Meet after 10 sec Meet after 1 sec Never meet Meet after 5 sec Meet after 10 sec Meet after 1 sec Never meet Meet after 5 sec ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics When a body of mass M1 is hanging freely and another of mass M2 lying on a smooth inclined plane(α) are connected by a light index tensile string passing over a smooth pulley, the acceleration of the body of mass M1, will be given by g(M1 + M2 sin α)/(M1 + M2) m/sec g(M1 - M2 sin α)/(M1 + M2) m/sec² g(M2 + M1 sin α)/(M1 + M2) m/sec² g(M2 × M1 sin α)/(M2 - M1) m/sec² g(M1 + M2 sin α)/(M1 + M2) m/sec g(M1 - M2 sin α)/(M1 + M2) m/sec² g(M2 + M1 sin α)/(M1 + M2) m/sec² g(M2 × M1 sin α)/(M2 - M1) m/sec² ANSWER DOWNLOAD EXAMIANS APP
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