Applied Mechanics and Graphic Statics The force polygon representing a set of forces in equilibrium is a Open polygon Closed polygon Parallelogram Triangle Open polygon Closed polygon Parallelogram Triangle ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics Newton’s Law of Motion is: The rate of change of momentum is directly proportional to the impressed force, and takes place in the same direction, in which the force acts To every action, there is always an equal and opposite reaction All listed here Everybody continues in its state of rest or of uniform motion in a straight line, unless it is acted upon by some external force The rate of change of momentum is directly proportional to the impressed force, and takes place in the same direction, in which the force acts To every action, there is always an equal and opposite reaction All listed here Everybody continues in its state of rest or of uniform motion in a straight line, unless it is acted upon by some external force ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A bullet weighing 10 gm moves with a velocity of l km/sec. Its kinetic energy is (i) 5000 Nm (ii) 5000 kg.m (iii) 5000 J Both (i) and (iii) Both (ii) and (iii) Only (ii) All (i), (ii) and (iii) Both (i) and (iii) Both (ii) and (iii) Only (ii) All (i), (ii) and (iii) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The angular speed of a car taking a circular turn of radius 100 m at 36 km/hr will be 100 rad/sec 1 rad/sec 0.1 rad/sec 10 rad/sec 100 rad/sec 1 rad/sec 0.1 rad/sec 10 rad/sec ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A string of length 90 cm is fastened to two points ‘A’ and ‘B’ at the same level 60 cm apart. A ring weighing 120 g is slided on the string. A horizontal force ‘P’ is applied to the ring such that it is in equilibrium vertically below ‘B’. The value of ‘P’ is: 60 g 100 g 40 g 80 g 60 g 100 g 40 g 80 g ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics In case of S.H.M. the period of oscillation (T), is given by T = 2π/ω T = 2/ω T = 2ω/π² T = π/2ω T = 2π/ω T = 2/ω T = 2ω/π² T = π/2ω ANSWER DOWNLOAD EXAMIANS APP
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