Refrigeration and Air Conditioning The difference between dry bulb temperature and wet bulb temperature, is called Degree of saturation Dew point depression Wet bulb depression Dry bulb depression Degree of saturation Dew point depression Wet bulb depression Dry bulb depression ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning Which of the following statement is wrong? The value of C.O.P. is always greater than one In a vapour compression system, the condition of refrigerant before entering the compressor is dry saturated vapour None of the listed here The space between the saturated liquid line and saturated vapour line, in a pressure enthalpy chart, is wet vapour region The value of C.O.P. is always greater than one In a vapour compression system, the condition of refrigerant before entering the compressor is dry saturated vapour None of the listed here The space between the saturated liquid line and saturated vapour line, in a pressure enthalpy chart, is wet vapour region ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning The process, generally used in winter air-conditioning to warm and humidity the air, is called Cooling and dehumidification Humidification Heating and humidification Dehumidification Cooling and dehumidification Humidification Heating and humidification Dehumidification ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning The colour of the flame of halide torch, in case of leakage of Freon refrigerant, will change to Orange Red Yellow Bright green Orange Red Yellow Bright green ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning In which of the following refrigeration system, waste heat can be effectively used? Vapour compression cycle None of the listed here Air refrigeration cycle Vapour absorption cycle Vapour compression cycle None of the listed here Air refrigeration cycle Vapour absorption cycle ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning A refrigerating system operating on reversed Brayton refrigeration cycle is used for maintaining 250 K. If the temperature at the end of constant pressure cooling is 300 K and rise in the temperature of air in the refrigerator is 50 K, then the net work of compression will be (assume air as working substance with Cp = 1 kJ/kg) 100 kJ/kg 125 kJ/kg 50 kJ/kg 25 kJ/kg 100 kJ/kg 125 kJ/kg 50 kJ/kg 25 kJ/kg ANSWER DOWNLOAD EXAMIANS APP
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