Concrete Technology and Design of Concrete Structures The depth of footing for an isolated column is governed byi) maximum bending momentii) shear forceiii) punching shearThe correct answer is only (i) (i), (ii) and (iii) (i) and (ii) (i) and (iii) only (i) (i), (ii) and (iii) (i) and (ii) (i) and (iii) ANSWER DOWNLOAD EXAMIANS APP
Concrete Technology and Design of Concrete Structures Modulus of elasticity of steel as per IS : 456-1978 shall be taken as 200kN/mm² 20 kN/cm² 2xl06N/cm² 200 kN/cm² 200kN/mm² 20 kN/cm² 2xl06N/cm² 200 kN/cm² ANSWER DOWNLOAD EXAMIANS APP
Concrete Technology and Design of Concrete Structures In a counterfort retaining wall, the main reinforcement is provided on the i) bottom face in front counterfort ii) inclined face in front counterfort iii) bottom face in back counterfort iv) inclined face in back counterEort The correct answer is (ii) and (iii) (iii) and (iv) (i) and (ii), (i) and (iv) (ii) and (iii) (iii) and (iv) (i) and (ii), (i) and (iv) ANSWER DOWNLOAD EXAMIANS APP
Concrete Technology and Design of Concrete Structures Maximum percentage reinforcement in case of slabs is limited to 9 2 4 8 9 2 4 8 ANSWER DOWNLOAD EXAMIANS APP
Concrete Technology and Design of Concrete Structures To determine the modulus of rupture, the size of test specimen used is 150 x150 x700 mm 150 x150 x500 mm 100 x100 x700 mm 100 x100 x500 mm 150 x150 x700 mm 150 x150 x500 mm 100 x100 x700 mm 100 x100 x500 mm ANSWER DOWNLOAD EXAMIANS APP
Concrete Technology and Design of Concrete Structures The relation between modulus of rupture fcr, splitting strength fcs and direct tensile strength fcl is given by fcr fcr>fcs>fc. fc5>fcr>fC tcr – rcs = tct fcr fcr>fcs>fc. fc5>fcr>fC tcr – rcs = tct ANSWER DOWNLOAD EXAMIANS APP
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