SSC JE Electrical 2019 with solution SET-1
 If the copper loss of a transformer at half full load is 400 W, then the copper loss corresponding to full load is

400 W
800 W
1600 W
1200 W

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SSC JE Electrical 2019 with solution SET-1
 Let T be the net torque developed by the rotor runs at ω rad/s. What is the mechanical power developed?

Pmech = (2πωT)
Pmech = (2πωT)/60
Pmech = ωT
Pmech = (ωT)/60

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SSC JE Electrical 2019 with solution SET-1
 The Norton’s current in the circuit shown below is

4A
12A
2A
120A

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SSC JE Electrical 2019 with solution SET-1
_______is a tube that brings water to turbines

Penstock
Trash rack
Forebay
Spillway

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