SSC JE Electrical 2019 with solution SET-1 The cheap and temporary system of the internal wiring is? Conduit wiring Cleat wiring CTS or TRS wiring Casing-capping Conduit wiring Cleat wiring CTS or TRS wiring Casing-capping ANSWER DOWNLOAD EXAMIANS APP
SSC JE Electrical 2019 with solution SET-1 When the only current source is active in the circuit, find the current through the 10Ω resistor 0 A 1.66 A 0.66 A 1.33 A 0 A 1.66 A 0.66 A 1.33 A ANSWER DOWNLOAD EXAMIANS APP
SSC JE Electrical 2019 with solution SET-1 At f = _____R – L – C series circuit operates at unity power factor 1 ⁄ RLC 1/RC 1 ⁄ LC 1/2π√LC 1 ⁄ RLC 1/RC 1 ⁄ LC 1/2π√LC ANSWER DOWNLOAD EXAMIANS APP
SSC JE Electrical 2019 with solution SET-1 The power factor of an A.C. circuit is equal to R/XC Z/R R/XL R/Z R/XC Z/R R/XL R/Z ANSWER EXPLANATION DOWNLOAD EXAMIANS APP In electrical engineering, the power factor of an AC electrical power system is defined as the ratio of the real power flowing to the load to the apparent power in the circuit ” R/Z”.
SSC JE Electrical 2019 with solution SET-1 The direction of the arrow represents the direction of when the diode is forward biased Conventional current flow N-type material P-N Junction P-type material Conventional current flow N-type material P-N Junction P-type material ANSWER EXPLANATION DOWNLOAD EXAMIANS APP The direction of the arrow represents the direction of the conventional current flow when the diode is forward biased.
SSC JE Electrical 2019 with solution SET-1 In the two wattmeter method, the readings of the two wattmeters are 500W, 500W respectively. The load power factor in a balanced 3-phase 3-wire circuit is: 0.5 1 0.9 0.8 0.5 1 0.9 0.8 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP In two wattmeter method the phase angle is tanφ = √3(W1 − W2)/(W1 + W2) tanφ = √3(500 − 500)/(500 + 500) tanφ = 0° φ = tan−10° = 0° Power factor = cosφ PF = cos0° = 1
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