SSC JE Electrical 2019 with solution SET-1
 If dΦ is the luminous flux incident normally on an area dA, then Illuminance is given as

Φ × A
dA ⁄ dΦ
dΦ ⁄ dA
dΦ − dA

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

SSC JE Electrical 2019 with solution SET-1
 The Norton’s current in the circuit shown below is

120A
12A
2A
4A

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP