Applied Mechanics and Graphic Statics The C.G. of a right circular cone lies on its axis of symmetry at a height of h/5 h/4 h/3 h/2 h/5 h/4 h/3 h/2 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The maximum displacement of a particle executing S.H.M. corresponds to Maximum kinetic energy and maximum potential energy Zero kinetic energy and maximum potential energy Minimum kinetic energy and minimum potential energy Zero potential energy and maximum kinetic energy Maximum kinetic energy and maximum potential energy Zero kinetic energy and maximum potential energy Minimum kinetic energy and minimum potential energy Zero potential energy and maximum kinetic energy ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The rate of change of displacement of a body with respect to its surrounding, is known Acceleration None of these Velocity Speed Acceleration None of these Velocity Speed ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If two bodies of masses M1 and M2(M1 > M2) are connected by alight inextensible string passing over a smooth pulley, the tension in the string, will be given by T = g(M2 + M1)/(M2 - M1) T = g(M1 - M2)/(M1 + M2) T = g(M1 + M2)/(M1 × M2) T = g(M2 - M1)/(M1 + M2) T = g(M2 + M1)/(M2 - M1) T = g(M1 - M2)/(M1 + M2) T = g(M1 + M2)/(M1 × M2) T = g(M2 - M1)/(M1 + M2) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics Two balls of masses 3 kg and 6 kg are moving with velocities of 4 m/sec and 1 m/sec respectively, towards each other along the line of their centers. After impact the 3 kg ball comes to rest. This can happen only if the coefficient of restitution between the balls is 2/3 1/5 1/3 3/5 2/3 1/5 1/3 3/5 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics ‘u₁’ and ‘u₂’ are the velocities of approach of two moving bodies in the same direction and their corresponding velocities of separation are ‘v₁’ and ‘v₂’. As per Newton's law of collision of elastic bodies, the coefficient of restitution (e) is given by e = u₂ - u₁/v₁ - v₂ e = v₁ - v₂/u₂ - u₁ e = v₂ - v₁/u₁ - u₂ e = v₁ - v₂/u₂ + u₁ e = u₂ - u₁/v₁ - v₂ e = v₁ - v₂/u₂ - u₁ e = v₂ - v₁/u₁ - u₂ e = v₁ - v₂/u₂ + u₁ ANSWER DOWNLOAD EXAMIANS APP
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