Engineering Mechanics The center of gravity of a quadrant of a circle lies along its central radius (r) at a distance of 0.8 r 0.5 r 0.6 r 0.7 r 0.8 r 0.5 r 0.6 r 0.7 r ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The moment of inertia of a thin disc of mass ‘m’ and radius ‘r’, about an axis through its center of gravity and perpendicular to the plane of the disc is mr²/2 mr²/4 mr²/6 mr²/8 mr²/2 mr²/4 mr²/6 mr²/8 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics One joule is equal to 100 N-m 1 N-m 0.1 N-m 10 N-m 100 N-m 1 N-m 0.1 N-m 10 N-m ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The principle of transmissibility of forces states that, when a force acts upon a body, its effect is Different at different points on its line of action Minimum, if it acts at the center of gravity of the body Same at every point on its line of action Maximum, if it acts at the center of gravity of the body Different at different points on its line of action Minimum, if it acts at the center of gravity of the body Same at every point on its line of action Maximum, if it acts at the center of gravity of the body ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The resultant of the two forces ‘P’ and ‘Q’ is ‘R’. If ‘Q’ is doubled, the new resultant is perpendicular to ‘P’. Then None of the listed here P = Q Q = 2R Q = R None of the listed here P = Q Q = 2R Q = R ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The unit of moment of inertia of an area is m4 kg-m2 kg/m2 kg-m-s2 m4 kg-m2 kg/m2 kg-m-s2 ANSWER DOWNLOAD EXAMIANS APP
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