Engineering Mechanics The center of gravity of a quadrant of a circle lies along its central radius (r) at a distance of 0.8 r 0.6 r 0.7 r 0.5 r 0.8 r 0.6 r 0.7 r 0.5 r ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics If ‘P’ is the force acting on the body, ‘m’ is the mass of the body and ‘a’ is the acceleration of the body, then according to Newton's second law of motion, P + m.a = 0 P × m.a = 0 P/m.a = 0 P - m.a = 0 P + m.a = 0 P × m.a = 0 P/m.a = 0 P - m.a = 0 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The angle between two forces when the resultant is maximum and minimum respectively are 180° and 0° 90° and 0° 90° and 180° 0° and 180° 180° and 0° 90° and 0° 90° and 180° 0° and 180° ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The Cartesian equation of trajectory is (where u = Velocity of projection, α = Angle of projection, and x, y = Co-ordinates of any point on the trajectory after t seconds.) y = (gx²/2u² cos²α) + x. tanα y = (gx²/2u² cos²α) - x. tanα y = x. tanα - (gx²/2u² cos²α) y = x. tanα + (gx²/2u² cos²α) y = (gx²/2u² cos²α) + x. tanα y = (gx²/2u² cos²α) - x. tanα y = x. tanα - (gx²/2u² cos²α) y = x. tanα + (gx²/2u² cos²α) ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics If the body falls freely under gravity, then the gravitational acceleration is taken as +9.8 m/s2 -8.9 m/s2 -9.8 m/s2 +8.9 m/s2 +9.8 m/s2 -8.9 m/s2 -9.8 m/s2 +8.9 m/s2 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Moment of inertia of a triangular section of base (b) and height (h) about an axis through its base, is bh3/12 bh3/36 bh3/4 bh3/8 bh3/12 bh3/36 bh3/4 bh3/8 ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS