Area Problems The area of a rectangle, 144 m long is the same as that of a square having a side 84 m long. The width of the rectangle is? 49 m 7 m 14 m Cannot be determined 49 m 7 m 14 m Cannot be determined ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area of the square = (84 + 84) m2Area of the rectangle = (144 x width) m2From question both area would be same,? Width = (84 x 84) / 144 m = 49 m
Area Problems Four horses are be tethered at four concern of a square plot of side 63 meters, so that they just cannot reach one another. The area left ungrazed is? 780.6 m2 850.5 m2 675.5 m2 785.8 m2 780.6 m2 850.5 m2 675.5 m2 785.8 m2 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area left ungrazed = [(63 x 63) - (4 x 1/4 x 22/7 x (63/2)2] m2= (63 x 63 - (99 x 63)/2 ) m2= 63 x (63 - 99/2) m2= 850.5 m2
Area Problems The area of the largest circle that can be drawn inside a rectangle with sides 18cm by 14cm is 1078 154 378 49 1078 154 378 49 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP The diameter is equal to the shortest side of the rectangle. So radius= 14/2 = 7cm. Therefore, area of circle = (r)2 = (22/7) x 49 = 154 cm2
Area Problems The length of hall is (4/3) times its breadth. If the area of hall be 300 square meters, the difference between the length and the breadth is? 15 meters 3 meters 4 meters None of these 15 meters 3 meters 4 meters None of these ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let breadth = b meters.Then, length = 4b/3 meters.? b x 4b/3 = 300? b2 = 300 x 3/4 ? b2 = 225? b = 15Hence, required difference = [(Length) - (Breadth) ]= 4b/3 - b = b/3= 15/3 m= 5 m
Area Problems The length of minute hand of a wall clock is 7 cms. The area swept by minute hand in 30 minutes is? 210 sq. cm 77 sq. cm 147 sq. cm 154 sq. cm 210 sq. cm 77 sq. cm 147 sq. cm 154 sq. cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Angle swept in 30 min= 180° Area swept = [(22/7) x 7 x 7] x [180°/360°] cm2 = 77 cm2
Area Problems The diameter of a wheel is 63 cms. Distance travelled by the wheel in 100 revolutions is? 99 meters 198 meters 63 meters 136 meters 99 meters 198 meters 63 meters 136 meters ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Distance travelled in 1 revolution = circumference of the wheel = ?d= ( 22/7 ) x 63= 198 cmSo the distance travelled in 100 revolutions = 100 x distance travelled in 1 revolution = 100 x 198 cm= 19800 cm = 198 m
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